Question

A six-sided fair die is rolled 4 times in a row. The probability of getting a 4 only on the last trial is

Answer 1

1/6 I am pretty sure

Answer 2

Answer:

The probability of getting a 4 only on the last trial is  $= \frac{125}{1296}$

Explanation:

When a die rolled single time, total number of favorable outcome is given as  {1,2,3,4,5,6}

when the die is rolled single time Probability of having  4 on die is

$= \frac{1}{6}$

and if die is roll and Probability of not having  4 is

$=1 - \frac{1}{6} = \frac{5}{6}$

Now, when die Rolled 4 times in a row, then probability of having  4 only on last trial is

$= \frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} \times \frac{1}{6}$

$= \frac{125}{1296}$