Question

Use the quadratic formula to find both solutions to the quadratic equation given below 4x^2+3x-1=0

Answer 1

    4x²  +  3x    -  1 = 0
a=4      b=3   c=-1

Quadratic formula:
x =$\frac{-b +/- \sqrt{b^{2} -4ac} }{2a} = \frac{-3 +/- \sqrt{3^{2} - 4(4)(-1)}}{2(4)}$
= $\frac{-3 +/- \sqrt{9 + 16}}{8} = \frac{-3 +/- \sqrt{25}}{8} = \frac{-3 +/- 5}{8}$
= $\frac{-3 + 5}{8}$ , $\frac{-3 - 5}{8}$
= $\frac{2}{8}$, $\frac{-8}{8}$
= $\frac{1}{4}$, -1

Answer 2

Answer: -1 and 1/4

Step-by-step explanation: a p e x