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creativ13 [48]
3 years ago
14

A professor at a local community college noted that the grades of his students were normally distributed with a mean of 74 and a

standard deviation of 10. Students who made 55 or lower on the exam failed the course. What percent of students failed the course?
Mathematics
1 answer:
denis-greek [22]3 years ago
6 0

Answer:

28.72% of students failed the course

Step-by-step explanation:

P(0<X<55) = normalcdf(0,55,74,10) = 0.287164928 = 28.72% of students failed the course

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Suppose that you have $5,000 to invest. Which investment yields the greater return over a 10 year period: 7.74% compounded daily
marin [14]

Answer:

We should invest in 7.74% compounded daily as it yields a higher return.

The total investment after 10 years is $10,841.22.

Step-by-step explanation:

<u>a.) at 7.74% compounded daily</u>

<u>final  = principal(1 +  \frac{i}{m} )^{m \times n}  \\  = 5000(1 +  \frac{0.0774}{365} )^{365 \times 10}  \\  = 10 \: 841.2235</u>

I assumed there are 365 days in a year.

<u>b</u><u>.</u><u>)</u><u> </u><u>a</u><u>t</u><u> </u><u>7</u><u>.</u><u>8</u><u>%</u><u> </u><u>c</u><u>o</u><u>m</u><u>p</u><u>o</u><u>u</u><u>n</u><u>d</u><u>e</u><u>d</u><u> </u><u>q</u><u>u</u><u>a</u><u>r</u><u>t</u><u>e</u><u>r</u><u>l</u><u>y</u>

<u>final = principal(1 +  \frac{i}{m}) ^{m \times n}   \\  = 5000 (1 +  \frac{.078}{4} )^{4 \times 10}  \\  = 10 \: 762.2505</u>

7 0
3 years ago
Write an algebraic expression that models the situation
ladessa [460]

Answer:

19

Step-by-step explanation:

just 19

5 0
4 years ago
8÷(3-1) _2 ×5-2<br>plssss help ​
Scilla [17]

Answer:

8

Step-by-step explanation:

You always start with the equasions in parenthesis. 3-1 is 2 and 8 divided by 2 is 4. Then you can move on to the next part of the eqasion. You start by subtracting 2 from 5 and then multiplying that by 2.then you add up the answers and you gat 8.

8 0
3 years ago
What is the circumference of a circle with an area of 50.24? Use 3.14 for pi.
kow [346]

Answer:

The answer is 200.96 cm^2.

2*3.14*r=50.24

=>r=50.24/6.28

=>r=8 cm

Thus area = 3.14*r*r

= 3.14*8*8

=200.96 cm^2

Step-by-step explanation:

4 0
4 years ago
A force of 3 pounds is required to hold a spring stretched 0.6 feet beyond its natural length. how much work (in foot-pounds) is
ioda

The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Work done (Wd) =?

<h3>How to determine the spring constant</h3>
  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Spring constant (K) =?

F = Ke

Divide both sides by e

K = F/ e

K = 3 / 0.6

K = 5 pound/foot

Thus, the spring constant of the spring is 5 pound/foot

<h3>How to determine the work done</h3>
  • Spring constant (K) = 5 pound/foot
  • Extention (e) = 0.7 feet
  • Work done (Wd) =?

Wd = ½Ke²

Wd = ½ × 5 × 0.7²

Wd = 2.5 × 0.49

Wd = 1.23 foot-pound

Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound

Learn more about spring constant:

brainly.com/question/9199238

#SPJ1

5 0
2 years ago
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