I need some major help with this proof.
2 answers:
Answer:
This one is actually in order already.
First box to A.
Second box to B
Third box to C.
Fourth box to D.
Fifth box to E.
Step-by-step explanation:
You always start with the given. So the first box goes to A.
The second box goes with B. When angle is bisected it is cut into two congruent halves. That means that left part of the angle of A has an equal measurement to that of the right part of the angle of A. So Angle BAD is congruent to Angle CAD.
Those base angles are B and C even though it isn't written there.
x (related) x is the reflexive property. This is what you have here where the related part is the congruence and the element being talking about is AD on both sides. So The third box goes with the reflexive option. The third box goes with C.
So you have by the given that AB and AC are congruent; those are the left and right leg of the big triangle.
You also have that Angle's BAD and CAD are congruent (those are the angles at the top in the two different triangles. You also have that they share the side right after.
So you are given 2 corresponding sides are congruent and the angle right between them in each is congruent.
We have enough information to prove the triangles are congruent by SAS. This fourth box should be matched with D.
Lastly, since the triangles are already congruent by SAS, then the other remaining corresponding sides are congruent and the other remaining corresponding angles are congruent. So Angle B and Angle C are congruent due to corresponding parts of congruent triangles are congruent. Last box is to be matched with E.
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