Evaluate: n + 8² if n = 2

It’s a 425 mile drive from San Jose to Los Angeles.

ICE Princess25 [194]

Answer:

The answer is below

Step-by-step explanation:

The distance traveled the first day = Distance from San Jose to Santa Barbara = 320 mile.

The distance traveled the second day = Distance from Santa Barbara to Los Angeles.

But From San Jose to Los Angeles = 425 mile. Therefore:

Distance From San Jose to Los Angeles = Distance from San Jose to Santa Barbara + Distance from Santa Barbara to Los Angeles

425 = 320 + Distance from Santa Barbara to Los Angeles.

Distance from Santa Barbara to Los Angeles = 425 - 320 = 105 mile

The distance traveled the second day = Distance from Santa Barbara to Los Angeles = 105 miles

The distance traveled the first day + The distance traveled the second day = Distance from San Jose to Santa Barbara + Distance from Santa Barbara to Los Angeles = 320 + 105 = 425 miles

The distance traveled the first day + The distance traveled the second day = 425 miles

6 0

3 years ago

The second one and the third one

Fynjy0 [20]

The answer to the thrd one is 52

how you do it is by multiplying the 6.5 by 8

and that gives your the answer of 52

idk about the other one cuz my answer came out to be .010 soooo ya idk if u should trust me on that one

anyways hope this helps!

5 0

3 years ago

Jeffery earned $65 doing yard work. He bought a pair of jeans for $31.25 and a sweat shirt for $16.50. He set aside the money le

erastova [34]

Answer:

Step-by-step explanation:

65.00 - 31.25 - 16.50 = $17.25

4 0

3 years ago

The length of overline CD is 12 units. C^ prime D^ prime is the image of overline CD under a dilation with a scale factor of n.

Rufina [12.5K]

Answer:

A, D , and E

Step-by-step explanation:

We have that:

$\overline{CD} = 12 \: units$

$\overline{C'D'}$

is the image of CD after a dilation of scale factor n.

We use the relation between the image length and object length:

$\overline{C'D'} = n \times \overline{CD}$

Option A

If n=3/2, then

$\overline{C'D'} = \frac{3}{2} \times 12 = 3 \times 6 = 18 \: units$

This is true.

Option B

If n=4, then

$\overline{C'D'} = 4 \times 12 = 36 \: units$

This is false.

Option C

If n=8, then

$\overline{C'D'} = 8 \times 12 = 96 \: units$

This too is false.

Option D

If n=2, then

$\overline{C'D'} = 2 \times 12 = 24 \: units$

This is true

Option E

If n=3/4, then

$\overline{C'D'} = \frac{3}{4} \times 12$

$\overline{C'D'} = 3 \times 3 = 9 \: units$

This is also true.

4 0

3 years ago

Felicia is solving the expression -5(3x+2)+10x. Gregory is solving the expression -12-4x+?+?x. Both students simplified their an

densk [106]

Answer:

see the explanation

Step-by-step explanation:

we have

<em>Felicia</em>

$-5(3x+2)+10x$

Apply distributive property

$-5(3x)-5(2)+10x$

$-15x-10+10x$

Combine like terms

$-5x-10$

Let

a ----> the missing term with coefficient x in Gregory's expression

b ----> the missing constant term in Gregory's expression

so

$-12-4x+ax+b$

equate Gregory's expression to Felicia's expression

$-12-4x+ax+b=-5x-10$

so

$-12+b=-10$ -----> $b=2$

$-4x+ax=-5x$ ------> $a=-1$

so

Gregory's expression is

$-12-4x+2-x$

therefore

The missing terms are 2 and -x

7 0

3 years ago