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Papessa [141]
2 years ago
7

Solve: 55) A pool is filling at 3 pts per min. How many gallons per hour is that?

Mathematics
1 answer:
Novay_Z [31]2 years ago
6 0
Conversion factors:
2 pints = 1 quart
4 quarts = 1 gallon
60 minutes = 1 hour

15 pints/minute x 60 minutes/hour x 1 quart/2 pints x 1 gallon/4 quarts = 112.5 gallons/hour
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kifflom [539]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
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7 t-shirts cost £67.55. How much do 11 t-shirts cost?
Oksanka [162]

Answer:

11 tshirts would cost £106.15

Step-by-step explanation:

67.55 divided by 7 = 9.65

9.65 x 11 = 106.15

Therefore the total would be £106.15.

4 0
3 years ago
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twice the number of donuts was only 6 less than 24 times the number of cream puffs. 10 times the number of cream puffs was only
Karolina [17]

donuts and cream puffs were  45 & 4 respectively !

<u>Step-by-step explanation:</u>

Here we have , twice the number of donuts was only 6 less than 24 times the number of cream puffs. 10 times the number of cream puffs was only 5 less than the number of donuts   We need to find how many donuts and cream puffs were there . Let's find out:

Let number of donuts and cream puffs are x & y respectively ! So ,

  • twice the number of donuts was only 6 less than 24 times the number of cream puffs

According to this statement equation is :

⇒ 2x=24y-6

⇒ x=12y-3            ................(1)

  • 10 times the number of cream puffs was only 5 less than the number of donuts

According to this statement equation is :

⇒ 10y= x-5

⇒ x=10y+5               ................(2)

Equation (1) & (2) :

⇒ 12y-3=10y+5

⇒ 2y=8

⇒ y=4

Putting  y=4 in  x=12y-3  :

⇒ x = 12(4)-3

⇒ x = 45

Therefore , donuts and cream puffs were  45 & 4 respectively !

7 0
3 years ago
Running out of time! Please help and show work! Thank you! Will mark brainliest!
VikaD [51]
<h3>​(-3j²k³)²(2j²k)³</h3>

(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.​</em>

​= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>

​= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>

= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.​</em>

= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹​

​Answer = 72j¹⁰k⁹

​Hope this helps!​​​​

​​\textit{\textbf{Spymore}}​​​​​​

5 0
3 years ago
1. Simplify. 5–1(3–2)
konstantin123 [22]

Answer with explanation:

Using following law of indices

1.x^a \times x^b=x^{a+b}\\\\2. (x^m)^n=x^{mn}\\\\ 3. x^{-n}=\frac{1}{x^n}\\\\4. \frac{x^m}{x^n}=x^{m-n}

1.5^{-1}\times 3^{-2}=\frac{1}{5}\times\frac{1}{3^2}\\\\=\frac{1}{5\times9}\\\\=\frac{1}{45}\\\\2. \frac{mn^{-4}}{p^0*q^{-2}}=\frac{mq^2}{n^4}\\\\ 3.0.0042=4.2\times 10^3\\\\4.6.12 \times 10^3=6.12 \times 1000=6120\\\\ 5.0.5 \times(8\times10^5})=\frac{1}{2}\times8 \times 10^5=4\times 10^5\\\\6. (9 \times 10^3)^2=9^2 \times (10^3)^2=81 \times 10^6\\\\7.( \frac{1}{2}a^{-4}\times b^2 )_{a=-2,b=4}{\text{or}}( \frac{1}{2}a^{4}\times b^{-2} )_{a=-2,b=4}=\frac{1}{2}\times (-2)^{-4}\times(4)^2{\text{or}}=\frac{1}{2}\times (-2)^{4}\times(4)^{-2}=\frac{16}{2\times16}=\frac{1}{2}

9. (4\times x\times y^2)^3\times (xy)^5=4^3\times x^3\times (y^2)^3\times x^5 \times y^5\\\\=64\times x^{3+5}\times y^{5+6}\\\\=64x^8y^{11}\\\\10.(2\times t^3)^3(0.4\times r)^2=2^3 \times (t^3)^3\times (0.4)^2 \times r^2=8\times t^9 \times 0.16 \times r^2=1.28r^2t^9

8. A number raised to a negative exponent is negative.

Explaining with the help of few examples

 1.2^{-3}=\frac{1}{2^3}=\frac{1}{8}\\\\ 2.(-3)^{-3}=\frac{1}{(-3)^{3}}=\frac{-1}{27}

Option C: Sometimes

1.Option B

2.Option A

3.Option C

4.Option A

5.Option D

6.  81 \times 10^6

7.Option B

8.Option C

9.Option A

10.Option  1.28 r^2 \times t^9

4 0
3 years ago
Read 2 more answers
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