Answer:
An area with younger people will have a higher demand for rentals and a lower demand for buying.- D.
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Based on the amount it would cost to build the machine and the interest rate as well as the payoff, the following are true:
a. The machine will take a year to build which means the payoff will only start coming in next year.
First find the present value of the perpetuity:
= 70 / 5%
= $1,400
You then need to find the present value of the above in the current period:
= 1,400 / ( 1 + 5%)
= $1,333
NPV is:
= 1,333 - 1,000 cost
= $333
B. If the amount produced increases by 1%, you should use the Gordon Growth Model:
<em>= Next payoff / ( Interest - Growth)</em>
=70/ ( 5% - 1%)
= $1,750
Take this to current year:
= 1,750 / 1.05
= $1,667
NPV will be:
= 1,667 - 1,000
= $667
Find out more about NPV at brainly.com/question/7254007.
Answer and Explanation:
The computation of the given question is shown below:-
Total Contributions = Monthly contribution + Amount invested in Ferdinand’s 401(k)
= $250 + $125
= $375
1. Future Value = PMT [((1 + r)n - 1) ÷ r
Future value = 375 × ((1 + 0.03 ÷ 12) × 12 × 40 - 1) ÷ (0.03 ÷ 12)
= $347,272
2. Ferdinand deposit = Given Amount × Total number of months in a year × Number of years
= $250 × 12 Months × 40 Years
= $120,000
3. The Amount put in by the employer = 50% of $250 ×Total number of months in a year × Number of years
=
$125 × 12 Months × 40 Years
= $60,000
4. Interest = Future value - Ferdinand deposit - The Amount put in by the employer
= $347,272 - $120,000 - $60,000
= $167,272
We simply applied the above formulas
Answer:
(a) 
(b) 
(c) X=4.975 percent
Explanation:
(a) Find the z-value that corresponds to 5.40 percent
.
Hence the net interest margin of 5.40 percent is 2.5 standard deviation above the mean.
The area to the left of 2.5 from the standard normal distribution table is 0.9938.The probability that a randomly selected U.S. bank will have a net interest margin that exceeds 5.40 percent is 1-0.9938=0.0062
(b) The z-value that corresponds to 4.40 percent is 
The net interest margin of 4.40 percent is 0.5 standard deviation above the mean.
Using the normal distribution table, the area under the curve to the left of 0.5 is 0.6915
Therefore the probability that a randomly selected U.S. bank will have a net interest margin less than 4.40 percent is 0.6915
(c) The z-value that corresponds to 95% which is 1.65
We substitute the 1.65 into the formula and solve for X.
A bank that wants its net interest margin to be less than the net interest margins of 95 percent of all U.S. banks should set its net interest margin to 4.975 percent.
