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Alja [10]
2 years ago
14

John is making baked goods for a party. He can either make muffins or bread, and he can use blueberries, bananas, apples, or cho

colate chips. Which table shows all of his possible options?.
Mathematics
1 answer:
Margarita [4]2 years ago
8 0

The total number of possible choices that John had for making baked goods for the party is 8.

<h3>What is Combination?</h3>

The combination helps us to know the number of ways an object can be arranged without a particular manner. A combination is denoted by 'C'.

^nC_r = \dfrac{n!}{r!(n-r)!}

where,

n is the number of choices available,

r is the choices to be made.

We know that the number of choices with John for his baked goods is only two which are muffins or bread, therefore, the choices of the baked good can be written as ^2C_1.

Also, the number of choices with John for flavors is four which are blueberries, bananas, apples, or chocolate chips, therefore, the choices of the flavor can be written as ^4C_1.

Now, the total possible choices that John had

= The choices of the baked good x The choices of the flavor

=\ ^2C_1 \times ^4C_1\\\\=\ 8

Hence, the total number of possible choices that John had for making baked goods for the party is 8.

Learn more about Combination:

brainly.com/question/11732255

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Answer:

The answers are \frac{2}{5}, \frac{1}{4}, \frac{1}{10}, \frac{5}{2}, \frac{5}{8}, \frac{4}{1}, \frac{8}{5}, and \frac{10}{1}.

Step-by-step explanation:

Proportions are fractions that can be made by using the given numbers, which in this case are 2, 5, 8, and 20. Let's pair each one with the other three and then simplify if possible.

First, let's begin with 2:

\frac{2}{5} = \frac{2}{5}

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Then, let's do 5:

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Note that we already have \frac{1}{4}, so we do not need to include an additional one.

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See how we already have \frac{2}{5}, so we won't have to include that as well.

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Now see that we already have both \frac{4}{1} and \frac{5}{2}, so we won't have to include both of them, as they are both extras.

Hence, the answers are \frac{2}{5}, \frac{1}{4}, \frac{1}{10}, \frac{5}{2}, \frac{5}{8}, \frac{4}{1}, \frac{8}{5}, and \frac{10}{1}.

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