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3 years ago

ABCD is a rhombus. = 5.5 cm and = 4 cm. What is the area of the rhombus?

1 answer:

4 0

Assuming that the two given values refer to the two diagonals of the rhombus, its area can be calculated using the formula: A = 0.5*p*q, where, p and q are the two diagonals. Substituting the values to the formula, we get the area of rhombus ABCD to be equal to 11 cm^2.

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100 POINTS

olga nikolaevna [1]

Answer:

5.2

Step-by-step explanation:

To find the height of the plant after 7 weeks, we need to find out the equation of the line of best fit and plug in 7 for x. We already have our y - intercept, which is 1, and we have a point on the x axis for which the y coordinate is an integer, (5, 4). Since we already have the y - intercept of +1 we have y = mx + 1. Since this applies to (5,4) we can plug this in to our equation. This is then 4 = 5m + 1. Subtracting 1 from both sides, we get 3 = 5m. Dividing by 5, we receive m = 3/5. Since now we have our slope, we can plug in 7 and find out our answer. Plugging in 7 we receive, y = 3/5 * 7 + 1, which is equal to y = 4.2 + 1. This means that y = 5.2, so 5.2 is our answer.

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3 years ago

Read 2 more answers

The length of a rectangle with area 38 in2 depends on its width. Write the formula that describes the length of the rectangle as

Ostrovityanka [42]

Answer:

L = 38/W

Step-by-step explanation:

The area of a rectangle is computed by multiplying length by width. For length L and width W in inches, your rectangle has area ...

A = LW

38 = LW

Then the length can be found by dividing the equation by W:

L = 38/W

8 0

3 years ago

Select the correct inequality for the graph below:

Lesechka [4]

the answer is D. y≤ -2x + 2

take x=2
then (-2 x 2) + 2
⇒ -4 + 2 = -2

4 0

3 years ago

Read 2 more answers

Task;2round off the following numbers to the highest place value.

eimsori [14]

Answer:

1.) 434 ____________

2.)5658 ____________

3.) 8374 ____________

4.) 361 ____________

5.) 7454 ____________

ito po ba ang i raround off

Step-by-step explanation:

answer:

1. 400

2.5000

3.8000

4.400

5.7000

kung ito po

#HOPE ITS HELP

7 0

2 years ago

The sales of a grocery store had an average of $8,000 per day. The store introduced several advertising campaigns in order to in

oksano4ka [1.4K]

Answer:

Null hypothesis: $\mu \leq 8000$

Alternative hypothesis: $\mu > 8000$

$z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2$

$p_v =P(Z>2)=0.0228$

Step-by-step explanation:

1) Data given and notation

$\bar X=8300$ represent the sample mean

$\sigma=1200$ represent the population standard deviation

$n=64$ sample size

$\mu_o =800$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 8000, the system of hypothesis are :

Null hypothesis: $\mu \leq 8000$

Alternative hypothesis: $\mu > 8000$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2$

4) P-value

Since is a one-side upper test the p value would given by:

$p_v =P(Z>2)=0.0228$

5) Conclusion

If we compare the p value and the significance level assumed, for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly higher than $8000.

4 0

3 years ago