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Fudgin [204]
2 years ago
9

How do I solve this literal equation? 15 points

Mathematics
1 answer:
kati45 [8]2 years ago
7 0

Answer:

\pi = \frac{A}{2r^2 + 2rh}

Step-by-step explanation:

First, we need to isolate \pi by taking it common from both terms on the right:

A=2\pi r^2 + 2\pi rh\\A=\pi (2r^2 + 2rh)

Now, since we want \pi in terms of the other variables, we can divide the left hand side (A) by whatever is multiplied with \pi on the right hand side. Then we will have an expression for \pi. Shown below:

A=\pi (2r^2 + 2rh)\\\pi = \frac{A}{2r^2 + 2rh}

This is the xpression for \pi

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Solve for n.<br> 4 x n= 21.6
Kay [80]

Answer:

n = 5.4

Step-by-step explanation:

Equation:  4n = 21.6

To solve this equation for n, divide both sides by 4 to get n by itself.

<u />

<u>Step 1:  Divide both sides by 4</u>

4 * n / 4 = 21.6 / 4

n = 5.4

Answer:  n = 5.4

3 0
2 years ago
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Which best describes the transformation that occurs from the graph of f(x) = x2 to g(x) = (x – 2)2 + 3?
Andrei [34K]

Answer:

A. right 2, up 3

Step-by-step explanation:

We have that,

The function f(x) = x^2 is transformed to g(x) =(x- 2)^2+3.

We see that,

The function f(x) is translated 2 units to the right and 3 units upwards to obtain the function g(x).

So, the correct transformation is 'right 2, up 3'.

Hence, option A is correct.

5 0
3 years ago
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What is the solution to the equation?<br><br>√2x+10−6=2<br><br><br>*Picture of the Problem Below*
Klio2033 [76]

Answer:

x = 27

Step-by-step explanation:

Given

\sqrt{2x+10} - 6 = 2 ( add 6 to both sides )

\sqrt{2x+10} = 8 ( square both sides )

2x + 10 = 8² = 64 ( subtract 10 from both sides )

2x = 54 ( divide both sides by 2 )

x = 27

5 0
3 years ago
I NEED THE ANSWER TO THIS ASAP FOR A TEST PLEASE!!!!!!!!
Varvara68 [4.7K]

Answer:

192

Step-by-step explanation:

you really should do your own test

A = lwh

A = 6 x 4 x 5 + 3

A = 6 x 4 x 8

A = 192

7 0
2 years ago
3(m - 4) &lt; 27
Free_Kalibri [48]

Step-by-step explanation:

This is right m does equal 13. D first you multiply everything in the para thesis and so on

6 0
2 years ago
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