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abruzzese [7]
3 years ago
10

Nicolette was swinging as high as she could on the 20 foot tall swing set on the playground while her lab partner, Robin, collec

ted
data on the swings.
For each swing Robin calculated the time and the height of Nicolette's swing as she reached the highest point, h. If she decided to
plot this information on a scatter plot, what would be a reasonable range of her graph?
A.
150 <h < 625
OB. 6<n< 10
6<h < 25
OD. 0<h <1​
Mathematics
1 answer:
djverab [1.8K]3 years ago
3 0
The answer is obvious a) i think lol
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Consider the following prisms, whose bases are both squares.
Alexxx [7]

Answer:

She did not establish that heights are the same.

Step-by-step explanation:

I just answered it.

7 0
2 years ago
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Which pair of angles is an example of supplementary angles?
artcher [175]

Answer:

A. Angle 1 and Angle 7

Step-by-step explanation:

Those two are the only angles that when added up, the sum is 180.

Angle 7 and Angle 2 are also congruent, so if Angle two forms a straight line with Angle 1, Angle 7 should be able to do that too.

6 0
2 years ago
Find the equation of the line that passes through the points (-5,7) and (2,3)
Olegator [25]

Answer:

y=-\frac{4}{7}x+4\frac{1}{7}

Step-by-step explanation:

So, in order to solve this problem, I started off by drawing it out. On my graph that I have attached below, I first started out by locating the points (-5,7) and (2,3). Now, this is an optional step, but I highly encourage practicing your graphing skills by solving this problem on graph paper as well. Next, I connected the two points that I just graphed. This is the line that passes through (-5,7) and (2,3).

Now, here is where the actual solving starts. If you haven't already been taught this yet, I will introduce it to you now. I am going to find the equation of this line by filling in what I know in the equation y=mx+b, where m= the slope of the line, and b= y intercept.

Slope of the line: m= \frac{y_{1} - y_{2}  }{x_{1} - x_{2}  } = \frac{7-3}{-5-2} = \frac{4}{-7}= -\frac{4}{7}

If you haven't been taught how to find the slope of a line I recommend you find out.

Substitute the slope into the equation.

y=-\frac{4}{7} x+b\\

Now, we will solve for the 'b,' or y intercept.

We already have x and y values to use: (-5,7) or (2,3). I'll use x=2 and y=3 to solve for the y intercept.

y=-\frac{4}{7} x+b\\\\3=-\frac{4}{7} *2+b\\\\3=-\frac{8}{7} +b\\b=3+\frac{8}{7} \\b=\frac{21}{7}+\frac{8}{7}=\frac{29}{7} =4\frac{1}{7} \\b=4\frac{1}{7}

Last step: substitute the slope and y intercept into y=mx+b.

y=mx+b\\y=-\frac{4}{7}x+4\frac{1}{7}

That is the answer to this problem.

I hope this helps.

3 0
3 years ago
Let point L be between M and N on MN. Given that MN=31, ML= h-15 and LN = 2h-8. Find LN
MrRa [10]

Since the distance of MN is 31 and we have a distance of ML of h -15 and LN of 2h – 8, therefore

ML + LN = h -15 + 2h – 8 = 31

 h = 18

substituting the value of h to the expression for LN obtaining

 

LN = 2h – 8

LN = 2(18) – 8

LN = 28

 

Therefore the length of the segment LN is 28 units

7 0
3 years ago
Subtract 37/55-32/55
lana66690 [7]
The answer would be 5/55 because if you subtract 32 from 37 you would end up with 5 and because the denominator was the same you keep the denominator the same.
5 0
3 years ago
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