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marishachu [46]
4 years ago
13

Find the derivative of f(x)=|x^2-1| at the point (1, 0) -1 0 1 Does not exist

Mathematics
1 answer:
slamgirl [31]4 years ago
4 0

Answer:

Does not exist.

Step-by-step explanation:

d/dx |u| = (u / |u|) * du/dx

Here u = x^2  - 1  and du/dx = 2x , so we have

2x (x^2 - 1) /  |x^2 - 1|    as the required derivative.

At the point (1,0)

the denominator = |1^2 - 1| = 0

- so  the derivative does not exist at (1, 0)

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