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Nutka1998 [239]
3 years ago
7

Complete the equation of the line whose y-intercept is (0, -1) and slope is 4. Stuck?

Mathematics
1 answer:
baherus [9]3 years ago
6 0

Answer:

y = 4x - 1

Step-by-step explanation:

equation of a line in slope-intercept form: y = mx + b

m is the slope and b is the y-intercept

y = 4x - 1

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The graph of a quadratic function with vertex (3,-2) is shown in the figure below.
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Solve, leaving in terms of a logarithm, with steps please! 160(0.4^x) +1=321
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Step-by-step explanation:

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3 years ago
Eargbkzvukuahdfbvvukhzdfbkufhbaw4jhbale&bLUsfhbvULHsfbf
pogonyaev

Answer:

a - 13/30

Step-by-step explanation:

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6 0
3 years ago
Which statement is true about the extreme value of the given quadratic equation? y = -3x2 + 12x − 33
Zina [86]

Answer:

The equation has a maximum value with a y-coordinate of -21.

Step-by-step explanation:

Given

y =-3x^2 + 12x - 33

Required

The true statement about the extreme value

First, write out the leading coefficient

Leading = -3

-3 < 0 means that the function would be a downward parabola;

Downward parabola always have their vertex on top of the parabola and as such, the function has a maximum value.

The maximum value is:

x = -\frac{b}{2a}

Where:

a= -3; b =12; c =-33

So, we have:

x = -\frac{12}{2 * -3}

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y = -3*2^2 + 12 * 2 - 33

y = -21

<em>Hence, the maximum is -21.</em>

8 0
3 years ago
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