To find the solution set we must factor the quadratic equation first.
7
- 28
= 7( [tex] q^{2} [/tex - 4)
= 7(x + 2)(x - 2) = 0
x = {-2, 2}
This means that if x equals -2, or 2 the whole expression would equal zero. Hope this helps!
7
= 7( [tex] q^{2} [/tex - 4)
= 7(x + 2)(x - 2) = 0
x = {-2, 2}
This means that if x equals -2, or 2 the whole expression would equal zero. Hope this helps!