-2/3
rise over run. plot the points and count.
Answer: the speed of the plane in still air is 135 miles per hour
the speed of the wind is 15 miles per hour
Step-by-step explanation:
Let x represent the speed of the plane in still air
Let y represent the speed of the wind.
The distance travelled by the plane is 600 miles.
Distance travelled = speed × time
It takes the plane 5 hours against the wind. This means that the total speed is (x-y) miles per hour. Therefore,
600 = 5(x- y) = 5x - 5y - - - - - - - 1
It takes the plane 4 hours with the wind. This means that the total speed is (x+y) miles per hour. Therefore,
600 = 4(x+ y) = 4x + 4y - - - - - - - - 2
Multiplying equation 1 by 4 and equation 2 by 5, it becomes
2400 = 20x - 20y
3000 = 20x + 20y
Adding both equations
5400 = 40x
x = 5400/40 = 135
Substituting x = 135 into equation 1, it becomes
4 × 135 + 4y = 600
540 + 4y = 600
4y = 600 - 540 = 60
y = 60/4 = 15
Answer:
(f⁻¹)'(b) = 1/f'(f⁻¹(b)) = 1/f'(a)
Step-by-step explanation:
The function f⁻¹(x) is the reflection of the function f(x) across the line y=x. Every point (a, b) that is on the graph of f(x) is reflected to be a point (b, a) on the graph of f⁻¹(x).
Any line with slope m reflected across the line y=x will have slope 1/m. (x and y are interchanged, so m=∆y/∆x becomes ∆x/∆y=1/m) Since f'(x) is the slope of the tangent line at (x, f(x)), 1/f'(x) will be the slope of the tangent line at (f(x), x).
Replacing x with f⁻¹(x) in the above relation, you get ...
... (f⁻¹)'(x) = 1/f'(f⁻¹(x)) will be the slope at (x, f⁻¹(x))
Putting your given values in this relation, you get
... (f⁻¹)'(b) = 1/f'(f⁻¹(b)) = 1/f'(a)
Answer:
850 songs
Step-by-step explanation:
3.4 ÷ 0.004 = 850
Hope this helps!! :)
Answer:
Input : 12
Output : -48
Step-by-step explanation:
Hope it helped
