Assuming this is the equation you want to operate on:
![v^{2} = (v_0)^{2} + 2\cdot a \cdot \Deltax](https://tex.z-dn.net/?f=%20v%5E%7B2%7D%20%3D%20%28v_0%29%5E%7B2%7D%20%2B%202%5Ccdot%20a%20%5Ccdot%20%5CDeltax%20)
![2\cdot a \cdot \Delta x = v^{2} - (v_0)^{2}](https://tex.z-dn.net/?f=%202%5Ccdot%20a%20%5Ccdot%20%5CDelta%20x%20%3D%20v%5E%7B2%7D%20-%20%28v_0%29%5E%7B2%7D%20)
![a = \frac{v^{2} - (v_0)^{2}}{2\cdot \Delta x}](https://tex.z-dn.net/?f=%20a%20%3D%20%5Cfrac%7Bv%5E%7B2%7D%20-%20%28v_0%29%5E%7B2%7D%7D%7B2%5Ccdot%20%5CDelta%20x%7D%20)
Before final operation we have to assume that x is not equal to 0. :)
Step-by-step explanation:
2x + 2y = 3 ( x2 for everything in the equation)
x - 4y = -1
4x+ 4y = 6
x - 4y = -1
Add the 1st line to the 2nd line to get rid of the y:
5x = 5
x - 4y = -1 ( you can pick any line from this system to be the second equation in this step, you can put 2x + 2y = 3 or 4x+ 4y = 6, anything above this step, but to make it simple chose the one you think is the easiest)
Solve for x, then plug the x value into the 2nd equation
x = 1
1 - 4y = -1
x = 1
-4y = -2 =) y = 1/2
x = 1
y= 1/2
The animal that shows the fastest change is the horse. The animal that shows that slowest rate of change is the mouse.
We can use graphs to find the rate of chabge by comparing. From using only the beginning and ending of the data, we would be finding the average rate of change over the specified period of time.
I think yes, my answers are reasonable.
I hope this helps :)
The answer would be -81t^2+16
Answer:
i believe it is a hexagon, since it has 5 sides