First I would change the descriptions of the numbers into expressions.
first number is n
second number is n + 6
third number is 4n (4 x n)
Then you would insert these expressions into an equation and isolate n.
n + n + 6 + 4n = 144
n + n + 4n = 144 - 6
6n = 138
n = 138/6
n = 23
Lastly, you would plug in this value into all of the expressions.
first number is 23
second number is 23 + 6 = 29
third number is 4(23) = 92
Therefore, the numbers are 23, 29, and 92.
1 x 48
2 x 24
3 x 16
4 x 12
6 x 8
Answer:
8.
Denote the equation : y = ax + b
Use the first 2 values of x and y in table:
3a + b = 21
5a + b = 35
Subtract the 2 equations:
=> 2a = 14 => a = 7 => b = 21 - 3 x 7 = 0
=> The solution is y = 7x
9.
Denote the equation : y = ax + b
Use the first 2 values of x and y in table:
5a + b = 17
10a + b = 22
Subtract the 2 equations:
=> 5a = 5 => a = 1 => b = 17 - 5 x 1 = 17 - 5 = 12
=> The solution is y = x + 12
Hope this helps!
:)
They stop at the same time after 4 times for the southbound bus to return and five times for the northbound bus returns to the bus stop
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~ hope this helps!
