One way to solve it is writing two equations based on the info so
y = 5x + 10 for members
y = 6x for nonmembers
(the + 10 isn't included in the second equation because nonmembers won't pay a membership fee)
and to find their intersection point (where the values will be the same), you just set them equal to each other:
5x + 10 = 6x
subtract 5x
x = 10 classes
Answer:
Total length of iron needed to make the square frame and two diagonals = 43.44 in (Approx)
Step-by-step explanation:
Given:
Length of diagonal = 9 in
Find:
Total length of iron needed to make the square frame and two diagonals.
Computation:
Area of square = 1/2(diagonal)²
Area of square = 1/2(9)²
Area of square = 40.5 in²
Area of square = Side × Side
40.5 in² = Side × Side
Side = 6.36 (approx)
Total length of iron needed to make the square frame and two diagonals = Permeter of square + (2 × diagonal)
⇒ (4 × 6.36) + (2 × 9)
⇒ (25.44) + (18)
⇒ 43.44 in
Total length of iron needed to make the square frame and two diagonals = 43.44 in (Approx)
Answer:
a = 11
Step-by-step explanation:
One is given the following equation:
3a - 7 = 26
Use inverse operations to solve this equation:
3a - 7 = 26
(add (7) to both sides)
3a = 26 + 7
Simplify,
3a = 26 + 7
3a = 33
Inverse operations,
3a = 33
(divide both sides by (3))
a = 33 / 3
Simplify,
a = 11
Answer:
The answer is 0
Step-by-step explanation:
0^2 is just 0x1 so 0+9=9
