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3 years ago

How do you find the inverse of a 3x3 matrix?

1 answer:

7 0

If you have a graphing calculaator enter the matrix then on the outside of it hit the ^ button and put -1

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if I found a place that will give me a 20% discount if I spent over $50 dollars my bill is 75 how much will I save

SVETLANKA909090 [29]

Your total will be $60, you will have saved $15

7 0

2 years ago

Pick any number and add 5 to it. Find the sum of the new number and the original number. Add 5 to the sum. Divide the new sum by

Oksana_A [137]

Answer: The final number is 5

Step-by-step explanation:

Picked number: 10

STEP are all according to what you stated

10+5=15 (first sentence)

15+10=25 (second sentence)

25+5=30 (third sentence)

30÷2-10=5 (fourth sentence)

The final number is 5.

3 0

3 years ago

7800 nm + 95 pm in scientific notation

azamat

$7800 nm+95pm=7800* 10^{-9} +95* 10^{-12}$
$=7800000* x^{-12} +95* 10^{-12} =7800095* 10^{-12} =7.800095* 10^{-6}$

3 0

3 years ago

Hey there! posted picture of question help please

Firdavs [7]

1. To answer the questions shown in the figure atttached, it is important to remember that the irrational number e is aldo called "Euler's number" and you can find it in many exercises in mathematics.

2. Then, the irrational number e is:

e=2.71828

3. When you rounded, you have:

e=2.718

4. Therefore, as you can see, the the correct answer for the exercise above is the option c, which is: c. 2.718

4 0

3 years ago

The volume of a rectangular box with a square base remains constant at 500 cm3 as the area of the base increases at a rate of 6

Andre45 [30]

Answer:

the rate at which the height of the box is decreasing is -0.0593 cm/s

Step-by-step explanation:

Given the data in the question;

Constant Volume of a rectangular box with a square base = 500 cm³

area of the base increases at a rate of 6 cm²/sec

so change in the area of the base with respect to time dA/dt = 6 cm²/sec

each side of the base is 15 cm long

so Area of the base = 15 cm × 15 cm = 225 cm²

the rate at which the height of the box is decreasing = ?

Now,

V = Ah

dv/dt = 0 ⇒ Adh/dt + hdA/DT = 0

⇒ dh/dt = -hdA/dt / A

we substitute

dh/dt = [ -( 500 / 225 ) × 6 ] / 225

dh/dt = [ -(2.22222 × 6) ] / 225

dh/dt = [ -13.3333 ] / 225

dh/dt = -0.0593 cm/s

Therefore, the rate at which the height of the box is decreasing is -0.0593 cm/s

7 0

2 years ago