Three consecutive integers add to 567. Find the integers. PLEASE HELP

1 answer:

7 0

Consecutive integers mean one after the other and their difference would one more or less.

Let the numbers be x, x +1, x +2.

Therefore x + (x+1) + (x +2) = 567
   3x + 3 = 567
   3x = 567 -3 = 564
   3x = 564 Divide by 3.
   x = 564/3
   x = 188
Therefore integers x, x +1, x +2 = 188, 188+1, 188+2.
      = 188, 189, 190.
Cheers.

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