1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
katovenus [111]
3 years ago
15

5(2x - 1) = 6 solve for

Mathematics
1 answer:
telo118 [61]3 years ago
6 0

the answer to your question is x= 11/10

You might be interested in
WILL NAME BRAINLIST!!
Novosadov [1.4K]

Answer:

D

Step-by-step explanation:

The fourth graph makes sense, and follows Deepak's equation. To check if a graph follows an equation, all you have to do is substitute the values of x and y into the equation and see if they follow the equation.

3 0
4 years ago
Read 2 more answers
Solve the right triangle​ ABC, with Cequals90degrees. Aequals58.3degrees​, cequals24.8 ft
horsena [70]

m∠B = 31.7° , a = 21.1 ft , b = 13.0 ft

Step-by-step explanation:

If ABC is a right triangle, where the right angle is B, then

  • The hypotenuse of the triangle is b and a , c are its legs
  • sin(A) = \frac{a}{b}
  • sin(C) = \frac{c}{b}
  • b=\sqrt{a^{2}+c^{2}}
  • The sum of the measures of the two acute angles A and C is 90°

∵ ABC is a right triangle

∵ m∠C = 90°

∴ c is the hypotenuse and a , b are its legs

∵ m∠A = 58.3°

- The sum of the two acute angles in the right triangle = 90°

∴ m∠A + m∠B = 90°

- Substitute the measure of angle A

∴ 58.3 + m∠B = 90

- Subtract 58.3 from both sides

∴ m∠B = 31.7°

∵ sin(A) = \frac{a}{c}

∵ c = 24.8 feet

∴ sin(58.3) = \frac{a}{24.8}

- By using cross multiplication

∴ a = (24.8) × sin(58.3)

∴ a = 21.1 ft

∵ sin(B) = \frac{b}{c}

∵ c = 24.8 feet

∴ sin(31.7) = \frac{b}{24.8}

- By using cross multiplication

∴ b = (24.8) × sin(31.7)

∴ b = 13.0 ft

m∠B = 31.7° , a = 21.1 ft , b = 13.0 ft

Learn more:

You can learn more about solving the triangle in brainly.com/question/12985572

#LearnwithBrainly

5 0
3 years ago
Are the graphs of 2x+7y=6 and 7y = 2x +6 parallel? Explain.
avanturin [10]
With questions like this (to see if theyre parallel), all you have to do is see if lines have a congruent slope. if yes (ex: 2 and 2), then they are parallel. if the slopes are opposites (ex: 4 and -1/4), then they are perpendicular. If they have no such relation (ex: -3 and 1/7), then they are neither.

with this problem, find the slope by separating the same variable in each equations, like this:

2x + 7y = 6
-2x            -2x

7y = -2x + 6

(the second equation is already separated) so now we have

7y = -2x + 6 and 7y = 2x + 6

since -2 does NOT equal 2, these two graphs/lines are NOT parallel.
Hope this helped!
7 0
3 years ago
1. A 5 gallon container of trail mix is 20% nuts. Another trail mix is added
Anton [14]

Answer:

800 nuts

Step-by-step explanation:

i hope this helps

4 0
2 years ago
Please help me i only have 4 minutes to turn this in u will get branliest for life!!!!!!!!!!!!!!!!!!!!11
zavuch27 [327]
Ok the answer is c!!!!!


8 0
3 years ago
Other questions:
  • Justify each step in solving the equation 4X equals seven times X -3
    6·2 answers
  • Complete the sentence below with less than,
    6·2 answers
  • Which expression shows the correct way to find the distance between<br> (23,17) and (43,14)? ( TTM)
    15·2 answers
  • Henry located 2 1/4 and 2.1 on a number line. He wrote the following related story:
    6·1 answer
  • 10p-2(3p-6)=4(3p-6)-8p please show work
    6·1 answer
  • Mr. Smith has 5 acres of land for sale. He divided the land into 3-acre lots. How many lots are for sale?
    9·1 answer
  • A rock climber ascends 18 feet to the top of a rock ledge. The climber
    11·1 answer
  • Which represents the area of this rectangle?
    13·2 answers
  • Please answer even if there is already 1, last time i asked this i put a lot of points and a bot took them and i dont have time
    6·1 answer
  • -3+p/7=-5 help step by step please ???
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!