Answer:
The average value of 
over the interval ![[-2,5]](https://tex.z-dn.net/?f=%5B-2%2C5%5D)
is 
.
Step-by-step explanation:
Let suppose that function is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of over the interval ![[-2, 5]](https://tex.z-dn.net/?f=%5B-2%2C%205%5D)
by algebraic handling:
![F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)](https://tex.z-dn.net/?f=F%285%29%20-%20F%283%29%20%2B%5BF%283%29-F%28-2%29%5D%20%3D%2040%20%2B%20%28-30%29)
The average value of over the interval is .
Step-by-step explanation:
let an amount be a
increase an amount by 10% and then by 30%
= a*1.1 *1.3 = a*1.43
The equation in slope intercept form is:
A line parallel to this would have the same slope, which means our line that passes through the point (0,-4) has a slope of -3. We now have to plug in 0 as our x and -4 as our y in y=-3x+b so:
Our equation is then y=-3x-b
