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pshichka [43]
3 years ago
8

Find all of the zeros of the function f(x)=x^3-17x^2+81x-65

Mathematics
1 answer:
viktelen [127]3 years ago
4 0
A graph shows the function can be factored as
  f(x) = (x -1)((x-8)² +1)

There is one real root and there are two complex roots. The latter can be found from the vertex form factor:
  (x - 8)² + 1 = 0
  (x - 8)² = -1
  x - 8 = ±√(-1) = ±i
  x = 8 ± i

The zeros of the function are {1, 8-i, 8+i}.

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A way you can set this up is like this.
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4 years ago
Solve: -x+3&gt;\:2x+1<br> Show your work<br> :)
scoundrel [369]

Answer:

X=7/6

Step-by-step explanation:

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3 years ago
Yo can somebody help me ?
Bess [88]

Answer:

x=60

Step-by-step explanation

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so 180 divided by 3= 60

thus your answer is 60

3 0
3 years ago
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Travka [436]

Answer:

x = 2°

steps:

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<u>reason</u>:

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