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lana [24]
3 years ago
9

Arrange your bookshelf with equal books In each row for a stack of 49 books.Decide if 49 is a prime number or a composite number

.List all the ways to present the books
Mathematics
1 answer:
mixas84 [53]3 years ago
6 0
49 is not a prime number, 7*7 is 49 so if you have 7 selves you can fit 7 books on to each self
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Which system of linear inequalities is graphed? {y>3x−2x+2y<4 {y≥3x−2x+2y≤4 {y≤3x−2x+2y≥4 {y<3x−2x+2y>4 A graph of a
guajiro [1.7K]

Answer:

{y≥3x−2

{x+2y≤4

3 0
2 years ago
Please use ( y = mx +b )
Sindrei [870]

Answer:

y= 2/5-1

Step-by-step explanation:

You get the 2/5 because you go 2 to the right and go 5 up, the -1 is because the x-int is at -1.

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2 years ago
I NEED HELP PLSS ITS LIKE 200 POINTS
zysi [14]

Answer:

y=-3/2x+3

Step-by-step explanation:

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This leaves the first and last choice only.

We can calculate the slope by 0-3 and 2-0, so -3/2 is the slope

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2 years ago
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9.72÷9 ___________________​
goldenfox [79]

Answer:

1.08

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8 0
3 years ago
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A manager of a grocery store wants to determine if consumers are spending more than the national average. The national average i
strojnjashka [21]

The valid conclusions for the manager based on the considered test is given by: Option

<h3>When do we perform one sample z-test?</h3>

One sample z-test is performed if the sample size is large enough (n  > 30) and we want to know if the sample comes from the specific population.

For this case, we're specified that:

  • Population mean = \mu = $150
  • Population standard deviation = \sigma = $30.20
  • Sample mean = \overline{x} = $160
  • Sample size = n = 40 > 30
  • Level of significance = \alpha = 2.5% = 0.025
  • We want to determine if the average customer spends more in his store than the national average.

Forming hypotheses:

  • Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get: H_0: \mu_0 \leq \mu = 150
  • Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically H_1: \mu_0 > \mu = 150

where \mu_0 is the hypothesized population mean of the money his customer spends in his store.

The z-test statistic we get is:

z = \dfrac{\overline{x} - \mu_0}{\sigma/\sqrt{n}} = \dfrac{160 - 150}{30.20/\sqrt{40}} \approx 2.094

The test is single tailed, (right tailed).

The critical value of z at level of significance 0.025 is 1.96

Since we've got 2.904 > 1.96, so we reject the null hypothesis.

(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).

Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.

Learn more about one-sample z-test here:

brainly.com/question/21477856

3 0
1 year ago
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