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Katen [24]
4 years ago
7

Please help me with these square root problems, Part 1. Please show and check the work.

Mathematics
2 answers:
garri49 [273]4 years ago
7 0

Answer:

x = 11

Step-by-step explanation:

sqrt (2x - 5) = sqrt (x + 6)

Square both sides

2x - 5 = x + 6

x = 11

Verify:

sqrt[2(11) - 5] = sqrt(11 + 6)

sqrt(17) = sqrt(17)

Arisa [49]4 years ago
4 0

Answer:

x = 11

Step-by-step explanation:

√2x-5 - √x+6 = 0

√2x-5 = √x+6

(√2x-5)² = (√x+6)²

2x - 5 = x + 6

2x - x = 6 + 5

x = 11

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The expression -120 + 13m represents a submarine that began at a depth of 120 feet below sea level and ascended at a rate of 13
Juli2301 [7.4K]

Answer:

It would be at a depth of 42 meters below the surface

Step-by-step explanation:

13(6)=78  -120+78=-42

8 0
3 years ago
What is the relationship between the number of vertices in each polygon and the number of isosceles triangles?
marshall27 [118]

Answer:

You didn’t post the figures so I’ll guess C lol

Step-by-step explanation:

5 0
3 years ago
Find the probability of picking a purple marble from a jar with 14 green and 14 purple<br> marbles.
iris [78.8K]

Step-by-step explanation:

n(s)=28

n(p)=14

p(p)= n(p)/n(s)

= 14/28

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4 0
3 years ago
An arithmetic sequence is defined by the recursive formula t1 = 11, tn = tn - 1 - 13, where n ∈N and n &gt; 1. Which of these is
galben [10]

coolio

t_1=11

t_n=t_{n-1}-13

so each term is ound by subtracting 13 from the previous term


an aritmetic sequence can be written as

t_n=t_1+d(n-1) were

t_n is the nth term

t_1 is the first term

d is common difference, which can also be found by doing t_n-t_{n-1}=d

n=wich term


we know that t_1=11 and we can find d

t_n=t_{n-1}-13, t_n-t_{n-1}=-13=d

so te general term is t_n=11-13(n-1) which can also be expanded and written as t_n=-13n+24

6 0
4 years ago
I’m really confused. Please help 。゚(゚´ω`゚)゚。
svp [43]

Answer:

4

Step-by-step explanation:

I say its 4 and it is 4

5 0
3 years ago
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