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3 years ago

A, b, c, or d?? im so bad at this dont even try me

Mathematics

1 answer:

Vika [28.1K]3 years ago

8 0

The median is 7. By definition of "median," half of the data values are below 7; half are above 7. Thus, the first statement is FALSE.

Spread: in the 2nd statement we are comparing the spread from lower quartile (4) to the median (7) and that from the median (7) to the upper quartile (9). In other words, we're comparing 3 to 2. This statement is TRUE.

The 3rd statement is the opp. of the 2nd statement, and thus is FALSE.

The 4th statement is FALSE. See my comments regarding the 1st statement.

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Please help me....people are just using my points and im running out.....please help me!!

storchak [24]

Answer

I think that c would equal 4

Step-by-step explanation:

If you need the explanation, here it is:

When looking at the y part of the answer, you can see it goes up by three and that it is missing a point. This means that if the equation is linear, it goes up by one. Hope that's right!!

5 0

3 years ago

Plz answer number 3 thx so much

nataly862011 [7]

The answer is isosceles and i think it's acute

6 0

3 years ago

Read 2 more answers

can someone please help me with this? i know it’s change of base formula i just don’t know how to work it out

ANTONII [103]

I still cant see it sorry cant help without seeing it can you spell the question?

3 0

3 years ago

What value of b will cause the system to have an infinite number of solutions?

irga5000 [103]

b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

<u>Solution: </u>

Need to calculate value of b so that given system of equations have an infinite number of solutions

$\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}$

Let us bring the equations in same form for sake of simplicity in comparison

$\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}$

Now we have two equations

$\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}$

Let us first see what is requirement for system of equations have an infinite number of solutions

If $a_{1} x+b_{1} y+c_{1}=0$ and $a_{2} x+b_{2} y+c_{2}=0$ are two equation

$\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$ then the given system of equation has no infinitely many solutions.

In our case,

$\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}$

As for infinitely many solutions $\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$

$\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}$

Hence b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

8 0

3 years ago

Please help solve all of these-

lana [24]

Answer:

3−y

2. 8

4.2bh

Step-by-step explanation:

5(2x+y)=15

2 Divide both sides by 55.

2x+y=\frac{15}{5}2x+y=

3 Simplify \frac{15}{5}

to 33.

2x+y=32x+y=3

4 Subtract yy from both sides.

2x=3-y2x=3−y

5 Divide both sides by 22.

x=\frac{3-y}{2}x=

1. 3−y

2. 8

2.Add 2y2y to both sides.

x=-8+2yx=−8+2y

2 Regroup terms.

x=2y-8x=2y−8

7 0

3 years ago