<span>1. In how many games does a girl play against a boy?
A: Because there are 5 girls, each will play against 5 boys, so in total is 5*5 = 25 times.
2. </span><span>In how many games does a girl play against another girl?
A: In this case, we only need to calculate how many girl pairs are there among these 5 girls, and it become a combination problem which can solved by </span>

3.The fraction of games "B vs B" should be the number of "B vs B" (which is 10) divide the total number of the games "B vs B" & "G vs G" & "B vs G" (which is 10+10+25=45, see the analysis in 1.A and 2.A), so the fraction should be 10/45=2/9
4.One person will have to play against 9 people at the tournament, and the total number of the games is 45, so the fraction should be 9/45 = 1/5
29 and 12! 29 + 12 comes out to 41 and 29 - 12 comes out to 17. I hope this helps!!
One tenth is 0.1. Therefore, the answer has to be 2.x. Since 4 is less than 5, the 2 remains the same. The answer is 2.2.
Answer:
b)$18
Step-by-step explanation:
The break even point is when the revenue is equal to the cost.
Revenue:
How much the store earns for each shirt.
We want to find the price of each shirt, and 50 shirts will be made.
So the revenue function is:

In which p is the price.
Costs:
A clothing store spends $10 for each shirt it produces and has fixed costs of $400.
So for 50 shirts:
400 + 50*10 = 900
Breakeven
Revenue equals cost
50p = 900
p = 900/50
p = 18
So the correct answer is:
b)$18
9514 1404 393
Answer:
(6,2)
Step-by-step explanation:
As is often the case with multiple-choice problems, you don't actually need to know the detailed working. You just need to know what the answer looks like.
When point X is dilated by a factor of 2 with point Z as the center of dilation, it will move to a location twice as far from Z. You can tell by looking at the graph that X' will be in the first quadrant, above and to the right of the location of X. The only sensible answer choice is ...
X' = (6, 2)
_____
<em>Additional comment</em>
X is a distance of X-Z = (4, 0) -(2, -2) = (2, 2) from Z Doubling that will put the image point a distance of 2(2, 2) = (4, 4) from Z. When this is added to Z, we find ...
X' = Z + (4, 4) = (2+4, -2+4) = (6, 2)