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gavmur [86]
3 years ago
12

What is the length of the focal width x=-1/8y^2

Mathematics
2 answers:
Levart [38]3 years ago
3 0
The standard equation is 4p(x-h) = (y-k)^2 where |p| = focal distance |4p| = focal width.

<span>x=-1/8y^2
-8x=y^2
4*(-2)(x-0) =( y-0)^2

p = -2, h=0, k=0</span><span>

focal width = |4*(-2)| = 8

The answer to your question is that the length of the focal width is equal to 8.</span>
muminat3 years ago
3 0

Answer:

The other person was right, the correct answer is 8

Step-by-step explanation:

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Step-by-step explanation:

Given

J_{Area} = 440

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<em>See attachment</em>

Required

Determine the area of K

First, we need to calculate the length of the rectangle  J

J_{Length} * J_{Width} = J_{Area}

This gives:

J_{Length} * 22 = 440

Divide both sides by 22

\frac{J_{Length} * 22}{22} = \frac{440}{22}

J_{Length} = 20

So, the length of the rectangle J is 20.

Since both shapes are similar, then:

J_{Length} : J_{Width} = K_{Length} : `K_{Width}

Substitute the known values:

20 : 22 = K_{Length} : `5.5

Express as fraction:

\frac{20 }{ 22 }= \frac{K_{Length} }{ `5.5}

Make Length, the subject of formula

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K_{Length} = \frac{110}{22}

K_{Length} = 5

The area of K is:

Area = K_{Length} * K_{Width

Area = 5.5 * 5

Area = 27.5

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Step-by-step explanation:

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I need help with this math problem
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