What is the length of the focal width x=-1/8y^2
2 answers:
The standard equation is 4p(x-h) = (y-k)^2 where |p| = focal distance |4p| = focal width.
<span>x=-1/8y^2
-8x=y^2
4*(-2)(x-0) =( y-0)^2
p = -2, h=0, k=0</span><span>
focal width = |4*(-2)| = 8
The answer to your question is that the length of the focal width is equal to 8.</span>
Answer:
The other person was right, the correct answer is 8
Step-by-step explanation:
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w=h/sinα, we are told that h=15 ft and α=70° so
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Answer:
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Step-by-step explanation:
3/4 = 0.75
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