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2 years ago

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What is the length of the focal width x=-1/8y^2

2 answers:

Levart [38]2 years ago

3 0

The standard equation is 4p(x-h) = (y-k)^2 where |p| = focal distance |4p| = focal width.

<span>x=-1/8y^2
-8x=y^2
4*(-2)(x-0) =( y-0)^2

p = -2, h=0, k=0</span><span>

focal width = |4*(-2)| = 8

The answer to your question is that the length of the focal width is equal to 8.</span>

muminat2 years ago

3 0

Answer:

The other person was right, the correct answer is 8

Step-by-step explanation:

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