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gavmur [86]
3 years ago
12

What is the length of the focal width x=-1/8y^2

Mathematics
2 answers:
Levart [38]3 years ago
3 0
The standard equation is 4p(x-h) = (y-k)^2 where |p| = focal distance |4p| = focal width.

<span>x=-1/8y^2
-8x=y^2
4*(-2)(x-0) =( y-0)^2

p = -2, h=0, k=0</span><span>

focal width = |4*(-2)| = 8

The answer to your question is that the length of the focal width is equal to 8.</span>
muminat3 years ago
3 0

Answer:

The other person was right, the correct answer is 8

Step-by-step explanation:

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OlgaM077 [116]

Given:

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\dfrac{4}{3}

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Marina86 [1]

Answer:

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Step-by-step explanation:

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3 years ago
17/21 ÷ 3 4/7 what us the estimated answer and steps to divide and find the answer
r-ruslan [8.4K]
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11.
Mrrafil [7]

Answer:

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Step-by-step explanation:

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