Ok I have the answers! Anything, whether positive or negative, with the value above .5 has a high correlation. Therefor the answers would be
B-low correlation
C-no correlation
D-low correlation
G- no correlation
I know that's too late for you but hope it helps with any other students struggling!
Answer:
Step-by-step explanation:
<u>Equation Solving</u>
We are given the equation:
![\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3y%2B16%7D%7B2y%2B9%7D%7D)
i)
To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.
We have to make it in steps like follows.
Cube both sides:
![\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%5E3%3D%5Cleft%28%5Csqrt%5B3%5D%7B%5Cfrac%7B3y%2B16%7D%7B2y%2B9%7D%7D%5Cright%29%5E3)
Simplify the radical with the cube:
Multiply by 2y+9
Simplify:
Operate the parentheses:
Subtract 3y and 
:
Factor y out of the left side:
Divide by 
:
ii) To find y when x=2, substitute:
Answer:
70 could represent the total number of points nolan can earn on the test
Step-by-step explanation:
<span>First we have to determine the slope of each lines by transforming to the slope-intercept form:
y=(3x-7/)4; m2= ¾y=(12x+6)/5, m3 = 12/5
The formula to be used in the proceeding steps is a=tan^-1(m1-m2)/1+m1m2=tan^-1(m1-m2)/1+m1m2
substituting, a=tan^-1(m1-3/4)/1+3m1/4=tan^-1(m1-12/5)1+12m1/5) =>(4m1-3)/(4+3m1)=(5m1-12)/(5+12m1)m1 = -1applying this slope
y -y1 = m(x-x1)
when y1 = 5 and x1 = 4 then,
y - 5 = -1(x-4)
y = -x +4+ 5 ; y = -x +9</span>
