Answer:
The equations that represent the reflected function are


Step-by-step explanation:
The correct question in the attached figure
we have the function

we know that
A reflection across the y-axis interchanges positive x-values with negative x-values, swapping x and −x.
therefore

The reflection of the given function across the y-axis will be equal to
(Remember interchanges positive x-values with negative x-values)

An equivalent form will be
![f(x)=5(\frac{1}{5})^{(-1)(x)}=5[(\frac{1}{5})^{-1})]^{x}=5(5)^{x}](https://tex.z-dn.net/?f=f%28x%29%3D5%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B%28-1%29%28x%29%7D%3D5%5B%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B-1%7D%29%5D%5E%7Bx%7D%3D5%285%29%5E%7Bx%7D)
therefore
The equations that represent the reflected function are


Answer:
25% increase
Step-by-step explanation:
Since the graph is a linear function, we're going to use the slope formula solve this:
Note I am replacing m with k

Inserting 2 points from the graph, let's use (1,8) and (2,16).

k=8