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LenKa [72]
3 years ago
13

Last Friday David rented 4 movies from the video store. This Friday he rented 2 movies. Let x represent the cost of renting each

movie. Write and simplify an expression for how much more David spent last week renting movies.
Mathematics
1 answer:
Likurg_2 [28]3 years ago
3 0

Expression:

4x - 2x

Simplified:

2x

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Suppose a dog can run 60 feet in 8 seconds. A cat can run 35 feet in 5 seconds. Which animal can run faster
Alika [10]

60/8 = 7.4. The dog is faster.  35/5 = 7

6 0
3 years ago
The population of a small industrial town was 12 910 in 2000. Each year, the population
balandron [24]

The population in the year 2020 is 4628

<h3>How to determine the population?</h3>

The given parameters are:

Initial, a = 12910

Rate, r = 5%

Since the population decreases, then we make use of an exponential decay function.

This is represented as:

f(n) = a * (1 - r)^n

So, we have:

f(n) = 12910 * (1 - 5%)^n

Evaluate the difference

f(n) = 12910 * 0.95^n

2020 is 20 years from 2000.

So, we have:

f(20) = 12910 * 0.95^20

Evaluate

f(20) = 4628

Hence, the population in the year 2020 is 4628

Read more about exponential functions at:

brainly.com/question/14355665

#SPJ1

6 0
2 years ago
I just need help with 6c. If you can, please explain how you got the answer.​
vagabundo [1.1K]

she could do multiplication AND division

3 0
3 years ago
Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x
Serggg [28]

I assume C has counterclockwise orientation when viewed from above.

By Stokes' theorem,

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

so we first compute the curl:

\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k

\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k

Then parameterize S by

\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k

where the z-component is obtained from

1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v

with 0\le u\le\dfrac\pi2 and 0\le v\le\dfrac\pi2.

Take the normal vector to S to be

\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k

Then the line integral is equal in value to the surface integral,

\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv

=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}

6 0
3 years ago
Phil gets a commission of 25% on all sales. He sold $1,500.00 worth of goods. What was the amount of his commission check?
Doss [256]

Answer:

the answer is 375.00 please leave a thanks id love that

6 0
3 years ago
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