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Serggg [28]
3 years ago
11

HELP I HAVE 6 MINUTES LEFT!!!!!!!!! 25 POINTS!!!!! Which answer is an equation in point-slope form for the given point and slope

? point: (−4,1) ; slope: 7
A.y+1=7(x−4)
B.y−1=7(x−4)
C.y−1=7(x+4)
D.y+1=7(x+4)
Mathematics
2 answers:
borishaifa [10]3 years ago
8 0

Equation:

y

−

4

=

6

(

x

−

7

)

The general form is:

y

−

y

0

=

m

(

x

−

x

0

)

where  

m

is the gradient and

the point is  

(

x

0

,

y

0

)


Valentin [98]3 years ago
8 0

The answer is c. y - 1 = 7(x+4)

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I need help with this problem, if anyone could help ASAP, that would be much appreciated. In the figure below, mROP = 125° Find
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Answer:

mRP = 125°

mQS = 125°

mPQR = 235°

mRPQ = 305°

Step-by-step explanation:

Given that

  • mROP = 125°
  • ∠ROP is a central angle

Then:

  • measure of arc RP, mRP = mROP = 125°

Given that

  • ∠QOS and ∠ROP are vertical angles

Then:

  • mQOS = mROP = 125°
  • measure of arc QS, mQS = mROP = 125°

Given that

  • ∠QOR and ∠SOP are vertical angles

Then:

  • mQOR = mSOP

Given that

  • The addition of all central angles of a circle is 360°

Then:

mQOS + mROP + mQOR + mSOP = 360°

250° + 2mQOR = 360°

mQOR = (360°- 250°)/2

mQOR = mSOP = 55°

And (QOR and SOP are central angles):

  • measure of arc QR, mQR = mQOR = 55°
  • measure of arc SP, mSP = mSOP = 55°

Finally:

measure of arc PQR, mPQR = mQOR + mSOP + mQOS = 55° + 55° + 125° = 235°

measure of arc RPQ, mRPQ = mROP + mSOP + mQOS = 125° + 55° + 125° = 305°

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