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3 years ago

The vertices of a quadrilateral are listed below.

Mathematics

1 answer:

suter [353]3 years ago

3 0

Answer:

D. The quadrilateral is a rhombus.

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you are going on vacation and leaving your dog in a kennel. kennel a charges $25 per day which includes a one-time grooming trea

rewona [7]

Answer:

is this a quiz?

Step-by-step explanation:

8 0

2 years ago

Population Growth The population P (in thousands) of Oriando,Florida from 1980 through 2009 can be modeled by p = 130e0.0205t,wh

svetoff [14.1K]

Answer: a) 236,000.

b) 2021

Step-by-step explanation:

Given : Population Growth The population P (in thousands) of Oriando,Florida from 1980 through 2009 can be modeled by $p = 130e^{0.0205t}$ (1)

where t = 0 corresponds to 1980.

Then , for 2009

t= 2009-1980=29

a. ⇒The population of Phoenix in 2009 = $p = 130e^{0.0205(29)}$

$p = 130e^{0.5945}$

$p =130(1.81212465608)=235.57620529\approx236$

Hence, the population of Orlando in 2009 was about 236,000.

b) Substitute p= 300 in (1) , we get

$300 = 130e^{0.0205t}$

$2.3077= e^{0.0205t}$ (Divide both sides by 130)

Taking Natural log on both sides,

$\ln(2.3077) = 0.0205t\\\\\Rightarrow\ t=\dfrac{\ln(2.3077)}{0.0205}$

$t=\dfrac{0.836251357528}{0.0205}=40.7927491477\approx41$

Hence, The year Orlando will have a population of 300,000 =1980+41 =2021

6 0

3 years ago

Find 30% of 70 whats your right one

qwelly [4]

Answer:

Step-by-step explanation:

I hope this helps!

3 0

2 years ago

Read 2 more answers

Tina left for school at 8:35 a.m. and she got back home at 3:45 p.m. How long was

a_sh-v [17]

Answer:

430 minutes or 7 hours and 10 minutes

Step-by-step explanation:

From 8:35 am to 9 am is 25 minutes. There are 60 minutes in an hour and 9 am to 3 pm is 6 hours. 3:00 to 3:45 pm is an additional 45 minutes.

60 minutes x 6 hours = 360 minutes

360 + 25 + 45 = 430 minutes

3 0

2 years ago

Read 2 more answers

Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.

charle [14.2K]

ANSWER

See below

EXPLANATION

Given

$f(x) = \frac{ {x}- 9 }{x + 5}$

and

$g(x) = \frac{ - 5x - 9}{x - 1}$

$(f \circ \: g)(x)= \frac{ (\frac{ - 5x - 9}{x - 1})- 9 }{(\frac{ - 5x - 9}{x - 1} )+ 5}$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9(x - 1)}{x - 1}}{\frac{ - 5x - 9 + 5(x - 1)}{x - 1} }$

Expand:

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9x + 9}{x - 1}}{\frac{ - 5x - 9 + 5x - 5}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9x + 9 - 9}{x - 1}}{\frac{ - 5x + 5x - 5 - 9}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 14x }{x - 1}}{\frac{ -14}{x - 1} }$

Since the denominators are the same, they will cancel out,

$(f \circ \: g)(x)= \frac{ - 14x}{ - 14} = x$

8 0

2 years ago