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Gennadij [26K]
3 years ago
12

33 points!! The line contains the point (4,-2) and is perpendicular to 4x+3y=-6 The equation of the line is:

Mathematics
1 answer:
Deffense [45]3 years ago
5 0

Answer:

y = 3/4 x - 5

Step-by-step explanation:

The slopes of perpendicular lines are negative reciprocals. We find the slope of the given line. Then we can find the slope of the reciprocal.

4x + 3y = -6

Solve for y.

3y = -4x - 6

y = -4/3 x - 2

The slope of the original line is -4/3.

The slope of the perpendicular is 3/4.

Now we need to find the equation of line with slope 3/4 that contains point (4, -2).

y = mx + b

-2 = (3/4)(4) + b

-2 = 3 + b

-5 = b

b = -5

The equation is

y = 3/4 x - 5

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We are given :

\sqrt{4x^{2}-20x+25}

Step 1: factor the part inside square root

The function given inside square root is of quadratic form.

So let us try to factorise it using AC method.

Here A*C = 4*25 = 100

so we have to find factors of 100 that add up to give -20.

the two factors are -10 and -10.

Rewriting the function :

4x^{2} -20x+25

=4x^{2} -10x-10x+25

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Step 2:

Now we take square root of the factorised form

\sqrt{(2x-5)^2}

= 2x-5

Answer : (2x-5)

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