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Nookie1986 [14]
3 years ago
11

How to resolve 81÷3=?

Mathematics
1 answer:
Lady_Fox [76]3 years ago
4 0

18/3= 27

therefore your answer is 27

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The produce manager at a market orders 10 lb of​ tomatoes, 20 lb of​ zucchini, and 40 lb of onions from a local farmer one week.
rewona [7]

Answer:

(A) A=\left[\begin{array}{ccc}10&20&40\end{array}\right]

(B) B=\left[\begin{array}{ccc}11&22&44\end{array}\right]

(C) A+B=\left[\begin{array}{ccc}21&42&84\end{array}\right]

Step-by-step explanation:

The manager ordered 10 lb of​ tomatoes, 20 lb of​ zucchini, and 40 lb of onions from a local farmer one week.

(A)

Matrix <em>A</em> represents the amount of each item ordered. ​It is 1 × 3 matrix.

Then matrix <em>A</em> is:

A=\left[\begin{array}{ccc}10&20&40\end{array}\right]

(B)

Next week the manager increases the order of all the products by 10%.

Then the amount of new orders are:

Tomatoes =10\times [1+\frac{10}{100}]=10\times1.10=11

Zucchini =20\times [1+\frac{10}{100}]=20\times1.10=22

Onions =40\times [1+\frac{10}{100}]=40\times1.10=44

Th matrix <em>B</em> represents the amount of each order for the next week. Then matrix <em>B</em> is:

B=\left[\begin{array}{ccc}11&22&44\end{array}\right]

(C)

Add the two matrix <em>A</em> and <em>B</em> as follows:

A+B=\left[\begin{array}{ccc}10&20&40\end{array}\right]+\left[\begin{array}{ccc}11&22&44\end{array}\right]\\=\left[\begin{array}{ccc}(10+11)&(20+22)&(40+44)\end{array}\right]\\=\left[\begin{array}{ccc}21&42&84\end{array}\right]

The entries of the matrix (<em>A</em> + <em>B</em>) represent the amount of tomatoes, zucchini and onions ordered for two weeks.

5 0
3 years ago
PLEASE HELP!!! Find each measure. m&lt;1, m&lt;2, m&lt;3
Mashcka [7]

Number 1: To find number 1 use hypotenuse theory. 180-(69+31) is the equation. After you solve it you get m<1 as 80.

Number 2: Since you already found m<1 find the other angle across from it.

Equation is: 180-80, which equals to 100.

Then once you have two angles use the theory again: 180-(100+45)=35.

Therefore m<2=35.

Number 3: Still using m<1, 180-100=80. Now you have to angles you get the equation:

180-(80+47), which equals to 53. Therefore m<3=53

Answers: m<1=80; m<2=35; m<3=53

5 0
3 years ago
Read 2 more answers
What is the median of the data?
eimsori [14]
<span>20, 19, 13, 23, 16, 15, 17, 17, 15, 15, 22, 19

</span>To find the Median, place the numbers in value order<span> and find the </span>middle<span>.
</span>
13, 15, 15, 15, 16, 17, 17, 19, 19, 20, 22, 23

There are 12 numbers and so we don't have just one middle number, we have a pair of middle numbers:


13, 15, 15, 15, 16, (17, 17), 19, 19, 20, 22, 23

<span>To find the value halfway between them, add them together and divide by 2:
</span>
17 + 17 = 34
34 ÷ 2 = 17

So the median is A) 17.

8 0
3 years ago
Which pair of complex numbers has a real-number product? (1 + 3i)(6i) (1 + 3i)(2 – 3i) (1 + 3i)(1 – 3i) (1 + 3i)(3i)
Kobotan [32]

Answer:

<h2>(1 + 3i)(1 – 3i) gives real number product</h2>

Step-by-step explanation:

Given the expressions

(1 + 3i)(6i) ,(1 + 3i)(2 -3i), (1 + 3i)(1 - 3i), (1 + 3i)(3i)

From analysis one of the following pairs has real-number products

(1 + 3i)(2 -3i), (1 + 3i)(1 - 3i)

Performing operations on

(1 + 3i)(2 -3i)= 2-3i+6-6i^2 \\= 2-3i+6-6(-1) \\=2-3i+6+6 \\=14-3i

Performing operations on

(1 + 3i)(1 - 3i) \\= 1-3i+3i-9(i)^2 \\= 1+0-9(-1) \\= 1+9=10

6 0
3 years ago
Question 6(Multiple Choice Worth 5 points)
blondinia [14]
6.50x + 5.25y + 15.25 <<span> 45
6.50(2)+5.25(3)+15.25<45
44<45
</span>
No because the total will be $44.
4 0
3 years ago
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