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dsp73
3 years ago
8

What are the coordinates of point S?

Mathematics
1 answer:
xxMikexx [17]3 years ago
8 0
CC. 2 units in positive x and 3 units in positive z
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Please help me i need to do this fast
andrezito [222]

It would be answer A since moving it right from the axis makes the x part include a negative next to the number that's being shifted from the axis, and when reflecting it across the x-axis, the number outside of the parenthesis becomes negative

3 0
3 years ago
can someone please help? And can you also explain how to do it, because I forgot the steps on how to do it ​
alexdok [17]

Answer:

option 3) EF= -7 FG= -7

Step-by-step explanation

X= 1/2

EF= 2X-8

    = 2 X 1/2 -8

    =1 - 8

EF = -7

FG= 4X -9

     = 4X 1/2

     2 - 9

FG     = -7

7 0
2 years ago
Assume that f(x)=ln(1+x) is the given function and that Pn represents the nth Taylor Polynomial centered at x=0. Find the least
WINSTONCH [101]

Answer:

the least integer for n is 2

Step-by-step explanation:

We are given;

f(x) = ln(1+x)

centered at x=0

Pn(0.2)

Error < 0.01

We will use the format;

[[Max(f^(n+1) (c))]/(n + 1)!] × 0.2^(n+1) < 0.01

So;

f(x) = ln(1+x)

First derivative: f'(x) = 1/(x + 1) < 0! = 1

2nd derivative: f"(x) = -1/(x + 1)² < 1! = 1

3rd derivative: f"'(x) = 2/(x + 1)³ < 2! = 2

4th derivative: f""(x) = -6/(x + 1)⁴ < 3! = 6

This follows that;

Max|f^(n+1) (c)| < n!

Thus, error is;

(n!/(n + 1)!) × 0.2^(n + 1) < 0.01

This gives;

(1/(n + 1)) × 0.2^(n + 1) < 0.01

Let's try n = 1

(1/(1 + 1)) × 0.2^(1 + 1) = 0.02

This is greater than 0.01 and so it will not work.

Let's try n = 2

(1/(2 + 1)) × 0.2^(2 + 1) = 0.00267

This is less than 0.01.

So,the least integer for n is 2

7 0
3 years ago
What is a car speed at 12 mile per 3 hours
Arturiano [62]
Hey there!
speed=distance/time.

s-speed

s=12/3
s=4

The speed of the car is 4 mph 

Hope this helps:) Let me know if you have any questions.
4 0
3 years ago
What is 5the answer 5t=t/45
Alexeev081 [22]
5t=\dfrac{t}{45}\\&#10;225t=t\\&#10;224t=0\\&#10;t=0
7 0
3 years ago
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