6x^2 - 2x + 1 is a quadratic formula from the form ax^2 + bx + c. This form of equation represents a parabola.
Finding 6x^2 - 2x + 1 = 0, means that you need to find the zeroes of the equation.
Δ = b^2 - 4ac
If Δ>0, the equation admits 2 zeroes and 6x^2 - 2x + 1 = 0 exists for 2 values of x.
If Δ<0, the equation doesn't admit any zero, and 6x^2 - 2x + 1 = 0 doesn't exist since the parabola doesn't intersect with the axe X'X
If Δ=0, the equation admits 1 zero, which means that the peak of the parabola is touching the axe X'X.
In 6x^2 - 2x + 1, a=6, b=-2, and c =1.
Δ= b^2 - 4ac
Δ=(-2)^2 - 4(6)(1)
Δ= 4 - 24
Δ= -20
Δ<0 so the parabola doesn't intersect with the Axe X'X, which means there's no solution for 6x^2 - 2x + 1 = 0.
I've added a picture of the parabola represented by this equation under the answer.
Hope this Helps! :)
The unknown number . . . . . (z)
The sum of the unknown number and 22 . . . . . (z + 22)
The sum of the unknown number and 22
divided by the same unknown number . . . . . . . (z + 22) / z
You said that quotient is 12. (z + 22) / z = 12
Multiply each side by 'z' : (z + 22) = 12 z
Subtract 'z' from each side: 22 = 11 z
Divide each side by 11 : 2 = z .
A, B, and C are the coefficients. They are not the terms as you have written now.
A quadratic equation is in the form Ax^2 + Bx + C. Therefore, A = 1, B = 8, and C = -6.
The axis of symmetry is found using the equation -b/2a, as you've done. Therefore, the axis of symmetry is -8/2(1) = -4.
Hope this helps!! :)
0.22 because one side is 11 and the other is 11 so 11+11 is 22 the pursent of 22 is 0.22