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4 years ago

By multiplying integers what is the total of (-10)(0)

Mathematics

1 answer:

34kurt4 years ago

3 0

Anything multiplied by 0 is zero. 100000 * 0 = 0, -1000 * 0 = 0.

Therefore, (-10)(0) = 0.

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A student has taken three math tests so far this semester His scores for the first three tests were 76, 80, and 84

Charra [1.4K]

Answer:

A=96% B=86%

Step-by-step explanation:

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3 years ago

Find h(x, y) = g(f(x, y)). g(t) = t + ln(t), f(x, y) = 4 − xy 2 + x2y2 h(x, y) =

san4es73 [151]

-2in = the equals sign has a slash through it 0

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3 years ago

What is the value of tan(60°)? One-half StartRoot 3 EndRoot StartFraction StartRoot 3 EndRoot Over 2 EndFraction StartFraction 1

Ratling [72]

Answer:

$\sqrt3$

Step-by-step explanation:

To find:

The value of $tan60^\circ$ = ?

Solution:

Kindly consider the equilateral $\triangle ABC$ as attached in the answer area.

Let the side of triangle = $a$ units

Let us draw the perpendicular from vertex A to side BC.

It will divide the side BC in two equal parts.

i.e. BD = DC = $\frac{a}{2}$

Using Pythagorean Theorem in $\triangle ABD$ :

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}$

Side AD = $\frac{\sqrt3}{2}a$

Using Trigonometric ratio:

$tan\theta = \dfrac{Perpendicular}{Base}$

$tanB = \dfrac{AD}{BD}$

Putting the values of AD and BD:

$tan60^\circ=\dfrac{\frac{\sqrt3}{2}a}{\frac{1}{2}a}\\\Rightarrow tan60^\circ = \bold{\sqrt3}$

5 0

3 years ago

Read 2 more answers

Consider the following system of two linear equations:

harkovskaia [24]

Hello,

Answer:

The last graph (2;3)

Step-by-step explanation:

2x + 3y = 12

2x – 3y = 0

2x + 3y = 12

2x = 3y

3y + 3y = 12 ⇔ 6y = 12 ⇔ y = 12/6 = 2

2x + 3 × 2 = 12 ⇔ 2x + 6 = 12 ⇔ 2x = 6 ⇔ x = 6/2 = 3

4 0

2 years ago

You are saving money to buy a used car. You deposit $2,500 in an account that earns interest compounded annually. The expression

seraphim [82]

Answer:

$r= [(\frac{A}{2500}) ^\frac{1}{2} -1]$

Step-by-step explanation:

Given data

Principal = $2500

time t= 2 years

Required

the rate r

Given the expression for the balance 2500(1+r)^2

Hence

$A= 2500(1+r)^2$

we can make r subject of formula

$r= [(\frac{A}{P}) ^\frac{1}{t} -1]$

$r= [(\frac{A}{2500}) ^\frac{1}{2} -1]$

Hence, for any value of A, we can find the rate using the expression above

6 0

3 years ago