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yKpoI14uk [10]
4 years ago
12

Which ordered pairs make both inequalities true? Select two options. y < 5x + 2 y > One-halfx + 1 On a coordinate plane, 2

straight lines are shown. The first solid line has a positive slope and goes through (negative 2, 0) and (0, 1). Everything above the line is shaded. The second dashed line has a positive slope and goes through (negative 1, negative 3) and (0, 2). Everything to the right of the line is shaded. (–1, 3) (0, 2) (1, 2) (2, –1) (2, 2)

Mathematics
1 answer:
Lena [83]4 years ago
8 0

Answer:

(1,2) and (2,2)

Step-by-step explanation:

we have

y ----> inequality A

The solution of the inequality A is the shaded area  below the dashed line y=5x+2

y\geq \frac{1}{2}x+1 ----> inequality B

The solution of the inequality B is the shaded area above the solid line y= \frac{1}{2}x+1

The solution of the system of inequalities is the shaded area below the dashed line A and above the solid line B

Remember that

If a ordered pair make both inequalities true, then the ordered pair is a solution of the system of inequalities

If a ordered pair is a solution of the system of inequalities, then the ordered pair lie in the shaded area of the solution set of the system

using a graphing tool

Plot the points and verify f the ordered pairs lies in the shaded area of the solution set

The solutions are the points (1,2) and (2,2)

see the attached figure to better understand the problem

Note The point (0,2) is not a solution because line A is a dashed line

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