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shutvik [7]
3 years ago
6

Help please :/

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
8 0
The maximum profit, as taught in calculus, can be determined when you equate the first derivative of the function to zero. So,

P' = 300 + 0

Hence, the maximum profit is 300.

I'm not sure about the vertices, though. Anyhow, I hope I was able to help you. Have a good day.

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Sarah has a bag of cherries. She ate 5, then gave half of what she had to Liam. Lam ate 5, then gave half of what he had to Amy.
Ksenya-84 [330]
I think Sarah had 12 cherries in the start
6 0
3 years ago
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Your school is selling granola bars for a fundraiser. They purchased 1250 granola bars and paid a delivery fee of $25. The total
MariettaO [177]
Hello!

First we have to define a variable.

Let x stand for the price of a granola bar

Then we have to make our equation

1250x + 25 = 800

This is the equation because the price for all the granola bars and delivery was $800

Now we solve it

Subtract 25 from both sides

1250x = 775

divide 1250 from both sides

x = 0.62

The cost for a granola bar is $0.62 or 62 cents

Hope this helps!
7 0
4 years ago
The following chart shows a store’s coat sales for two years.
STALIN [3.7K]

Answer:

Sales of trench coats increased 8.3 percentage points faster than total coat sales.

Step-by-step explanation:

<u>2006:</u>

top coats is 297,

parkas is 210,

jackets is 213,

raincoats is 137,

trench coats is 103

Total: 297+210+213+137+103=960

<u>2007:</u>

topcoats is 223,

parkas is 210,

jackets is 285,

raincoats is 259,

trench coats is 127

Total: 223+210+285+259+127=1,104

<u>Percent increase in total sales:</u>

\dfrac{1,104-960}{960}\cdot 100\%=15\%

<u>Percent increase in sales of trench coats:</u>

\dfrac{127-103}{103}\cdot 100\%\approx 23.3\%

Since 23.3\%-15\%=8.3\%, sales of trench coats increased 8.3 percentage points faster than total coat sales.

7 0
3 years ago
Read 2 more answers
Line Symmetry and Reflections help?
QveST [7]

5.(8)

6. (D)

Hope this helped

8 0
4 years ago
Read 2 more answers
Can someone help me with the Log. question please?
mr Goodwill [35]
U can change it by using the rule of logarithm.
log (10/y)= log10 - log y
6 0
3 years ago
Read 2 more answers
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