Just sub in (x+1) wherever x appears:
f(x) = 2x+4
f(x+1) = 2(x+1)+4 = 2x + 2 + 4 = 2x+6
Answer:
D. The work shown above is correct, and ![y^5.\sqrt[4]{y^3}](https://tex.z-dn.net/?f=y%5E5.%5Csqrt%5B4%5D%7By%5E3%7D)
may not be simplified further.
Step-by-step explanation:
![\sqrt[4]{y^{23} } = \sqrt[4]{y^4 . y^4 . y^4.y^4.y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7By%5E%7B23%7D%20%7D%20%3D%20%5Csqrt%5B4%5D%7By%5E4%20.%20y%5E4%20.%20y%5E4.y%5E4.y%5E3%7D)
![\sqrt[4]{y^4. y^4.y^4. y^4.y^3} = y^5 . \sqrt[4]{y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7By%5E4.%20y%5E4.y%5E4.%20y%5E4.y%5E3%7D%20%3D%20y%5E5%20.%20%5Csqrt%5B4%5D%7By%5E3%7D)
When we simplify, we get
![\sqrt[4]{y^{23} } = y^5.\sqrt[4]{y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7By%5E%7B23%7D%20%7D%20%3D%20y%5E5.%5Csqrt%5B4%5D%7By%5E3%7D)
The answer: D. The work shown above is correct, and ![y^5. \sqrt[4]{y^3}](https://tex.z-dn.net/?f=y%5E5.%20%5Csqrt%5B4%5D%7By%5E3%7D)
may not be simplified further.
Thank you.
Im pretty sure that it would be 4 but not sure
Answer:
7
Step-by-step explanation:
2
Answer:
Los pasajeros pasan por el ____.
a.
equipaje
c.
maletero
b.
control de seguridad
d.
mostrador
Step-by-step explanation:
