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2 years ago

12

In which number is the value of the digit 5 greater? Write

1 answer:

Arte-miy333 [17]2 years ago

6 0

Answer:

43.5

Step-by-step explanation:

In the first option it's two away from the decimal meaning it is equal to 5/100 while in the second option it's one away from the decimal so it is worth half

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The answer is C trust me I did this

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Here is a histogram showing Barry Bonds's home-run totals for the years 1991 - 2005. Looking at the histogram, you might suspect

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3 years ago

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Érica has saved $24, which is 40% of the total amount she needs to buy a new video game. How much does she need total to buy the

d1i1m1o1n [39]

Do 40/100=24/x and cross multiply

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3 years ago

There are some Nichols dimes and quarters in a large piggy bank for every two nickels there a sweetheart forever to Diane’s ther

grigory [225]

Answer:

There are 80 nickels, 120 dimes and 300 quarters in the piggy bank.

All coins in the piggy bank worth $91.

Step-by-step explanation:

Please consider the complete question:

There are some nickels, dimes, and quarters in a large piggy bank. For every 2 nickels there are 3 dimes. For every 2 dimes there are 5 quarters. There are 500 coins total. How many nickels, dimes, and quarters are in the piggy bank? Explain your reasoning. How much are the coins in the piggy bank worth?

Let n, d, q represent number of nickles, dimes and quarters respectively.

For every 2 nickels there are 3 dimes. We can represent this information in an equation as:

$\frac{2}{n}=\frac{3}{d}...(1)$ or

$n=\frac{2d}{3}...(1)$

For every 2 dimes there are 5 quarters. We can represent this information in an equation as:

$\frac{2}{d}=\frac{5}{q}...(2)$ or

$q=\frac{5d}{2}...(2)$

There are 500 coins total. We can represent this information in an equation as:

$n+d+q=500...(3)$

We will use substitution method to solve our given system.

Upon substituting equation (1) and equation (2) in equation (3), we will get:

$\frac{2d}{3}+d+\frac{5d}{2}=500$

Multiply the equation by 6:

$\frac{2d}{3}*6+d*6+\frac{5d}{2}*6=500*6$

$2d*2+6d+5d*3=3000$

$4d+6d+15d=3000$

$25d=3000$

$\frac{25d}{25}=\frac{3000}{25}$

$d=120$

Therefore, there are 120 dimes in the piggy bank.

Upon substituting $d=120$ in equation (1), we will get:

$n=\frac{2(120)}{3}$

$n=2(40)$

$n=80$

Therefore, there are 80 nickels in the piggy bank.

Upon substituting $d=120$ in equation (2), we will get:

$q=\frac{5d}{2}$

$q=\frac{5(120)}{2}$

$q=5(60)$

$q=300$

Therefore, there are 300 quarters in the piggy bank.

Now, we need to find the value of all coins.

We know 1 quarter is worth $0.25, so 300 quarters will be worth $\$0.25\times 300=\$75$ .

We know 1 dime is worth $0.10, so 120 dimes will be worth $\$0.10\times 120=\$12$ .

We know 1 nickel is worth $0.05, so 80 nickels will be worth $\$0.05\times 80=\$4$ .

$\text{All coins worth}=\$75+\$12+\$4$

$\text{All coins worth}=\$91$

Therefore, all coins in the piggy bank worth $91.

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3 years ago

Solve the compound inequality. –1 < 4m + 7 ≤ 11 A. −14

ankoles [38]

This is what I got :-(

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3 years ago