Answer:
Binomial with a degree of 3
Step-by-step explanation:
-8m^3 + 11m....notice that it has 2 terms....(-8m^3) and (11m). Having 2 terms makes it a binomial...if it would have had 3 terms, it would have been a trinomial. If it has only one variable, the degree is the highest exponent...so this has a degree of 3 since ^3 is the highest exponent.
so the answer is : binomial with a degree of 3
Points on given line = (-12,-2) and (0,-4) because you can see them on the graph. Then draw a parallel line thru (0,6)
To get from (0,-4) to (0,6) your x stays constant and your y coordinate increased by 10. So your new point will do the same in relation to (-12,-2) the x will stay constant at -12 and your y will increase by 10 to +8.
So the answer is A (-12,8)
You can check this because parallel lines have the same slope so
y2-y1/x2-x1 should be equal for both lines.
Line 1: -4 - (-2) / 0 - (-12) = -2/12 = -1/6
Line 2: 6 - 8 / 0 - (-12) = -2/12 = -1/6
Answer:
48
Step-by-step explanation:
here, we are using an = ar^n-1
so, we have to find a4= ar^4-1 = ar^3
now, putting the given values in the equation,
a4= (6)(2)^3 = 6(8) = 48
therefore, the 4th term is 48.
<em>I</em><em> </em><em>have </em><em>done </em><em>this </em><em>question</em><em> </em><em>previously</em><em> </em><em>on </em><em>Gauthmath</em><em> </em><em>app,</em><em> </em><em>you </em><em>can </em><em>check </em><em>that </em><em>app </em><em>out,</em><em> </em><em>really </em><em>cool </em><em>app.</em><em> </em>
<em>A</em><em>l</em><em>l</em><em> </em><em>the</em><em> best</em><em> </em><em>with </em><em>your </em><em>exam.</em><em> </em><em />
59 degrees!
because you set up your problem: 3c+2+2c-7=90
then combine all like terms: 5c-5=90
Add 5 to both sides: 5c=95
then divide both sides by 5: c=19
Plug in your answer: 3(19)+2=59
Answer:
First, I think the right formula is:
A) We first derive the formula given above:
V'(t) represent the drain rate of the tank volume.
B) the units is: gallons/time
C) at V'(10) = 100000/60 = 1666.66 gallons/time.
because the formula V'(t) is constant so it doesn't depend of time.
