Answer:
2
Step-by-step explanation:
Simplify the following:
(-(2 + 2/3))/(-(1 + 1/3))
(-(2 + 2/3))/(-(1 + 1/3)) = (-1)/(-1)×(2 + 2/3)/(1 + 1/3) = (2 + 2/3)/(1 + 1/3):
(2 + 2/3)/(1 + 1/3)
Put 1 + 1/3 over the common denominator 3. 1 + 1/3 = 3/3 + 1/3:
(2 + 2/3)/(3/3 + 1/3)
3/3 + 1/3 = (3 + 1)/3:
(2 + 2/3)/((3 + 1)/3)
3 + 1 = 4:
(2 + 2/3)/(4/3)
Put 2 + 2/3 over the common denominator 3. 2 + 2/3 = (3×2)/3 + 2/3:
((3×2)/3 + 2/3)/(4/3)
3×2 = 6:
(6/3 + 2/3)/(4/3)
6/3 + 2/3 = (6 + 2)/3:
((6 + 2)/3)/(4/3)
6 + 2 = 8:
(8/3)/(4/3)
Multiply the numerator by the reciprocal of the denominator, (8/3)/(4/3) = 8/3×3/4:
(8×3)/(3×4)
(8×3)/(3×4) = 3/3×8/4 = 8/4:
8/4
The gcd of 8 and 4 is 4, so 8/4 = (4×2)/(4×1) = 4/4×2 = 2:
Answer: 2
Answer:
Tn = 64-4n
Step-by-step explanation:
The nth term of an AP is expressed as:
Tn = a+(n-1)d
a is the common difference
n is the number of terms
d is the common difference
Given the 6th term a6 = 40
T6 = a+(6-1)d
T6 = a+5d
40 = a+5d ... (1)
Given the 20th term a20 = -16
T20 = a+(20-1)d
T20 = a+19d
-16 = a+19d... (2)
Solving both equation simultaneously
40 = a+5d
-16 = a+19d
Subtracting both equation
40-(-16) = 5d-19d
56 = -14d
d = 56/-14
d = -4
Substituting d = -4 into equation
a+5d = 40
a+5(-4) = 40
a-20 = 40
a = 20+40
a = 60
Given a = 60, d = -4, to get the nth term of the sequence:
Tn = a+(n-1)d
Tn = 60+(n-1)(-4)
Tn = 60+(-4n+4)
Tn = 60-4n+4
Tn = 64-4n
Answer:
A, complementary angles sum up to 90°
