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3 years ago

9

Which equation can be used to find the value of X?

1 answer:

ollegr [7]3 years ago

6 0

Answer:

d

Step-by-step explanation:

Just put it equal to 180.

2x+5+4x-11+90=180

6x+84=180

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Kobotan [32]

There are 99 miles left. 43(7)=301. 400-301=99.

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3 years ago

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Hello I really need help with this

Harman [31]

Answer:

<u>7</u>

Step-by-step explanation:

The sides are in proportion.

$\frac{AC}{DF} = \frac{AB}{DE}$
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nikitadnepr [17]

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4 years ago

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4 years ago

Find the linear approximation of the function g(x) = 3 1 + x at a = 0. g(x) ≈ Correct: Your answer is correct. Use it to approxi

EleoNora [17]

Answer:

$3.296x+3$

2.835

3.330

Step-by-step explanation:

$g(x) = 3^{1+x}$

Let the linear approximation be L(x) at a = 0. This is given by

$L(x) = g(a) + g'(a)(x-a)$

$g'(x)$ is the derivative of $g(x)$ . To find this, we use the form

If $f(x) = a^x$ , then $f'(x) =a^x\ln a$

By doing this and applying chain rule for the power (which is a function of x), we have

$g'(x) = 3^{1+x}\ln 3$

Then

$g'(0) = 3^{1+0}\ln 3 = 3.296$

Also $g(0) = 3^{1+0} = 3$

Hence $L(x) = 3+(x-0)\times3.296 = 3.296x + 3$

For $3^{0.95}$ , $1+x = 0.95$ and $x=-0.05$

Using this in $L(x)$ ,

$3^{0.95} = 3.296(-0.05) + 3 = 2.835$

For $3^{1.1}$ , $1+x = 1.1$ and $x=0.1$

Using this in $L(x)$ ,

$3^{1.1} = 3.296(0.1) + 3 = 3.330$

7 0

4 years ago