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sergeinik [125]
3 years ago
12

Im trying to find the measure of the numbered angle:)??

Mathematics
2 answers:
bazaltina [42]3 years ago
4 0
3 and 2 would be 122 since 3 and the 58° are a linear pair making them add up to 180. And 3 and 2 are vertical so they would be congruent.
4 would then have to be 38 since the three angles would have to measure up to 180.
And the 1 would have to be 36 with the same reasoning as before.
Disclamier (I might have done some math wrong since I did it in my head.)
irakobra [83]3 years ago
4 0

As Angle(2) and Angle(3) are Vertically Opposite Angles, they should be Equal.

Let us Take Angle(2) = Angle(3) = X

The Opposite Angle to 58° will also be 58° as they are Vertically Opposite Angles.

We can Notice that Angle(2), Angle(3) and Both the 58° Angles together make a Complete Angle (i.e. 360°)

⇒ Angle(2) + Angle(3) + 58° + 58° = 360°

⇒ Angle(2) + Angle(3) + 116° = 360°

⇒ Angle(2) + Angle(3) = 360° - 116°

⇒ Angle(2) + Angle(3) = 244°

⇒ X + X = 244°

⇒ 2X = 244°

⇒ X = 122°

We took Angle(2) = Angle(3) = X

⇒ Angle(2) = Angle(3) = 122°

Now let us go for the Upper Triangle :

As Sum of Angles in a Triangle = 180°

Angle (1) + Angle(2) + 22° = 180°

Angle (1) + 122° + 22° = 180°

Angle (1) + 144° = 180°

Angle (1) = 180° - 144°

Angle (1) = 36°

Now let us go for the Lower Triangle :

As Sum of Angles in a Triangle = 180°

Angle (3) + Angle(4) + 20° = 180°

Angle (4) + 122° + 20° = 180°

Angle (4) + 142° = 180°

Angle (4) = 180° - 142°

Angle (4) = 38°

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Please help me out guys. The photo will show you what to do. 50 points cause I need it done fast
Nonamiya [84]

Answer:

a) starting height: 5.5 ft

b) hang time: 5.562 seconds

c) maximum height: 126.5 ft

d) time to maximum height: 2.75 seconds

Step-by-step explanation:

a) The starting height is the height at t=0.

h(0) = -16·0 +88·0 +5.5

h(0) = 5.5

The starting height is 5.5 feet.

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b) The ball is in the air between t=0 and the non-zero time when h(t) = 0. We can find the latter by solving ...

-16t^2 + 8t +5.5 = 0

t^2 -(11/2)t = 5.5/16 . . . . . subtract 5.5, then divide by -16

t^2 -(11/2)t +(11/4)^2 = (5.5/16) +(11/4)^2 . . . . complete the square

(t -11/4)^2 = 126.5/16 . . . . . . . . . . . . . . . . . . . . call this [eq1] for later use

t -11/4 = √7.90625

t = 2.75 +√7.90625 ≈ 5.562

The ball will be in the air about 5.562 seconds.

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c) If we multiply [eq1] above by -16 and add the constant on the right, we get the vertex form of the height equation:

h(t) = -16(t -11/4) +126.5

The vertex at (2.75, 126.5) tells us ...

The maximum height of the ball is 126.5 feet.

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d) That same vertex point tells us ...

The maximum height will be reached at t = 2.75 seconds.

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If you really need answers fast, a graphing calculator can give them to you in very short order (less than a minute).

6 0
3 years ago
6 sweets cost 42p altogether how much do 8 sweets cost
Eddi Din [679]
The best thing to do is to find the cost of one sweet, and to do this, divide 42 by 7.
42/7= 6
Therefore, one sweet costs 6p.
To find the cost of 8 sweets, you've got to multiply 6 by 8, and this gives you 54p.
Therefore, 8 sweets cost 54p
This is basically just finding unit rate and multiplying.
<span>Hope this helps :)</span>
8 0
3 years ago
Read 2 more answers
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