The answer is g) y= 27.6 and x=11
1.5y=41.4
1.5y/1.5=41.4/1.5
y=27.6
Answer:
2 RootIndex 4 StartRoot 4 EndRoot
Step-by-step explanation:
we have
Decompose the number 64 in prime factors
substitute
![64^{\frac{1}{4}}=(2^{4}2^{2})^{\frac{1}{4}}=2^{\frac{4}{4}}2^{\frac{2}{4}}=2\sqrt[4]{4}](https://tex.z-dn.net/?f=64%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D%282%5E%7B4%7D2%5E%7B2%7D%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D2%5E%7B%5Cfrac%7B4%7D%7B4%7D%7D2%5E%7B%5Cfrac%7B2%7D%7B4%7D%7D%3D2%5Csqrt%5B4%5D%7B4%7D)
The area of the table is 3.75 feet
The boxes are .83333 feet by .83333 feet so that area is .69
.69x3 is 2.07 so yes they will fit on top of the table
Answer:
A) 0.4255
B) 0.5813
C) 0.5588
D) 0.7241
Step-by-step explanation:
Assuming that the probability for each case is the same, we can calculate the probability by dividing the number of favourable cases with the total amount of cases. You can find the total amount of cases by adding the favourable ones with the non favourable ones, so, the probability of each case would be:
A) 20/(27+20) = 20/47 = 0.4255
B) 25/(18+25) = 25/43 = 0.5813
C) 19/(15+19) = 19/34 = 0.5588
D) 21((8+21) = 21/29 = 0.7241
Answer:
Yes the y value an have more than one x value BUT the x value can only have one y value.
Step-by-step explanation:
example if we have 1 and it goes to 2 the 1 cant go to another number such as 3.. if we had another number like 4 and it goes to 2 like the 1 it would be acceptable
hope this helped and is not to confusing-
