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4 years ago

6x+7y=4x+4y Complete the missing value in the solution

Mathematics

1 answer:

Alex4 years ago

7 0

Answer:

complete the missing value in the solution

Step-by-step explanation:

Simplifying

6x + 7y = 4x + 4y

Solving

6x + 7y = 4x + 4y

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.

6x + -4x + 7y = 4x + -4x + 4y

Combine like terms: 6x + -4x = 2x

2x + 7y = 4x + -4x + 4y

Combine like terms: 4x + -4x = 0

2x + 7y = 0 + 4y

2x + 7y = 4y

Add '-7y' to each side of the equation.

2x + 7y + -7y = 4y + -7y

Combine like terms: 7y + -7y = 0

2x + 0 = 4y + -7y

2x = 4y + -7y

Combine like terms: 4y + -7y = -3y

2x = -3y

Divide each side by '2'.

x = -1.5y

Simplifying

x = -1.5y

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A hypothesis will be used to test that a population mean equals 10 against the alternative that the population mean is less than

Nonamiya [84]

Answer:

Lets take the hypothesis

zα/2 

- zα/2 

Step-by-step explanation:

α/2 = 0.10/2 = 0.05 

z(0.05) = 3.92 

-z(0.05) = -3.92 

4 0

3 years ago

Please help I really need it for a grade boost.

ArbitrLikvidat [17]

Answer:

I hope This will Help u.. Plz mark me as Brilliant please

Step-by-step explanation:

Before you get started, take this readiness quiz.

Simplify:

If you missed this problem, review (Figure).

Solve Equations with Constants on Both Sides

In all the equations we have solved so far, all the variable terms were on only one side of the equation with the constants on the other side. This does not happen all the time—so now we will learn to solve equations in which the variable terms, or constant terms, or both are on both sides of the equation.

Our strategy will involve choosing one side of the equation to be the “variable side”, and the other side of the equation to be the “constant side.” Then, we will use the Subtraction and Addition Properties of Equality to get all the variable terms together on one side of the equation and the constant terms together on the other side.

By doing this, we will transform the equation that began with variables and constants on both sides into the form We already know how to solve equations of this form by using the Division or Multiplication Properties of Equality.

Solve:

Solution

In this equation, the variable is found only on the left side. It makes sense to call the left side the “variable” side. Therefore, the right side will be the “constant” side. We will write the labels above the equation to help us remember what goes where.

Since the left side is the “”, or variable side, the 8 is out of place. We must “undo” adding 8 by subtracting 8, and to keep the equality we must subtract 8 from both sides.

Use the Subtraction Property of Equality.Simplify.Now all the variables are on the left and the constant on the right.

The equation looks like those you learned to solve earlier.Use the Division Property of Equality.Simplify.Check:Let .

Solve:

Solution

Notice, the variable is only on the left side of the equation, so we will call this side the “variable” side, and the right side will be the “constant” side. Since the left side is the “variable” side, the 9 is out of place. It is subtracted from the , so to “undo” subtraction, add 9 to both sides. Remember, whatever you do to the left, you must do to the right.

4 0

3 years ago

Read 2 more answers

GEOMETRY! PLEASE SHOW YOUR WORK. (updated picture)

Orlov [11]

Given:

The base of the given triangle has two part:

Left( left side of the hypotenuse) = 25

Right ( right side of the hypotenuse) = x

The altitude (h) = 60

To find the value of x.

Formula:

By Altitude rule we know that, the altitude of a triangle is mean proportional between the right and left part of the hypotenuse,

$\frac{left}{altitude} =\frac{altitude}{right}$

Now,

Putting,

left = 25, altitude = 60 and right = x we get,

$\frac{25}{60} =\frac{60}{x}$

or, $(25)(x )=(60)(60)$ [ by cross multiplication]

or, $x = \frac{3600}{25}$

or, $x = 144$

Hence,

The value of x is 144.

6 0

3 years ago

Read 2 more answers

Assume that you have a sample of n 1 equals 6, with the sample mean Upper X overbar 1 equals 50, and a sample standard deviati

tigry1 [53]

Answer:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

$df=6+5-2=9$

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

$n_1 =6$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

$\bar X_1 =50$ represent the sample mean for the group 1

$\bar X_2 =38$ represent the sample mean for the group 2

$s_1=7$ represent the sample standard deviation for group 1

$s_2=8$ represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

We are assuming that the population variances for each group are the same

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic for this case is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

We can find the pooled variance:

$S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67$

And the pooled deviation is:

$S_p=7.46$

The statistic is given by:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

The degrees of freedom are given by:

$df=6+5-2=9$

The p value is given by:

$p_v =P(t_{9}>2.656) =0.0131$

4 0

4 years ago

Assume that all six outcomes of a six-sided number cube have the same probability. What is the theoretical probability of each r

Margarita [4]

Hey there! I am on the same one. :) I will help you out a little.

Assume that all six outcomes of a six-sided number cube have the same probability. What is the theoretical probability of each roll?
• 1: 1/6
• 2: 2/6
• 3: 3/6
• 4: 4/6
• 5: 5/6
• 6: 6/6

Using the uniform probability model you developed, what is the probability of rolling an even number?
1/6 Roll a number cube 25 times. Record your results here.

 1st toss=6 2nd toss=4 3rd toss=6 4th toss=6 5th toss=3 6th toss=3 7th toss=4 8th toss=2 9th toss=6 10th toss=5 11th toss=1 12th toss=4 13th toss = 5 14th toss =1 15th toss=4 16th toss=2 17th toss=2 18th toss=2 19th toss=6 20th toss=5 21st toss=3 22nd toss=4 23rd toss=3 24th toss=3 25 toss=5
How many results of 1 did you have? __2____________ How many results of 2 did you have? ____4__________ How many results of 3 did you have? ____5__________ How many results of 4 did you have? ______5________ How many results of 5 did you have? ______4________ How many results of 6 did you have? ______5________
Based on your data, what is the experimental probability of each roll? 1. 2/25 or 0.08

2. 4/25 or 0.16

3. 5/25 or 0.24

4. 5/25 or 0.2

5.4/25 or 0.16

6. 5/25 or 0.2Using the probability model based on observed frequencies, what is the probability of rolling an even number? 3/6 = ½ or 0.5
Was your experimental probability different than your theoretical probability? Why or why not? It somewhat is! The denominator is 25 for the experimental probability, and 6 for the theoretical probability.
Have a lovely day! Cheerio. :)

8 0

4 years ago

Read 2 more answers