All categories

3 years ago

What are the measures of ∠1, ∠2, and ∠3? Enter your answers in the boxes.

Mathematics

1 answer:

GarryVolchara [31]3 years ago

3 0

Answer: m<1 is 60, m<2 is 60, and m<3 is 120

Step-by-step explanation:

M<1 is 60 and m<2 is also 60 because the interior triangle angles have to equal 180 so M<1 + m<2 + 60 = 180 so m<1 and m<2 are both sixty.

m<3 is 120 because m<2 and m<3 are supplementary so if a supplementary angle is equal to 180 then m<2 + m<3 = 180 and m<2 is 60 so m<3 is 120.

You might be interested in

-8=-(x+4) what is the answer

Tems11 [23]

Step 1: Flip the equation.
−
x
+
4
=
−
8
Step 2: Subtract 4 from both sides.
−
x
+
4
−
4
=
−
8
−
4
−
x
=
−
12
Step 3: Divide both sides by -1.
−
x
−
1
=
−
12
−
1
x
=
12
Answer:
x
=
12

5 0

2 years ago

Harrison has 90 CDS in his music collection. If 40% of those CDS are country music and 50% are pop, how many CDS are other types

Ksenya-84 [330]

10% CDS are other types of music

4 0

3 years ago

Alright I need The answers for number 27 please reply To This question I posted

lys-0071 [83]

Answer:

C. Sqrt(12^2+9^2)

Step-by-step explanation:

Pythagorean theorem is

x^2+y^2=z^2

So solving for z

z=sqrt(x^2+y^2)

z=sqrt(9^2+12^2)

6 0

3 years ago

Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data

tresset_1 [31]

Based on the information represented by the boxplot ;

Latasha's lowest sale amount = 50

Kayla's median is between 200 and 300

Latasha has a greater spread due to higher IQR value

1.) The Lowest amount of sale made by Latasha in one month

The minimum value is denoted by the starting position of the lower whisker on a boxplot.

Lowest amount of sale made by Latasha = 50

2.) 50% of sales made by Kayla :

50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

50% of sales made by Kayla is between 200 and 300

With median sale value being 250

3.) Spread of the middle 50% of sales :

The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

IQR = Upper Quartile (Q3) - Lower quartile(Q1)

For Latasha :

Q3 = 450 (Endpoint of the box)
Q1 = 150 (starting point of the box)

IQR = 450 - 150 = 300

For Kayla :

Q3 = 375 (Endpoint of the box)
Q1 = 100 (starting point of the box)
IQR = 375 - 100 = 275

Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

4 0

2 years ago

The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds.Refer to

Dafna11 [192]

Given that

the weight of football players is distributed with a mean of 200 pounds and a standard deviation of 25 pounds.

And we need to find What is the minimum weight of the middle 95% of the players?

Explanation -

Using the Empirical Rule, 95% of the distribution will fall within 2 times of the standard deviation from the mean.

Two standard deviations = 2 x 25 pounds = 50 pounds

So the minimum weight = 200 pounds - 50 pounds = 150 pounds

Hence the final answer is 150 pounds.

3 0

1 year ago