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Schach [20]
3 years ago
14

How to multiply (x + 1)^3

Mathematics
2 answers:
ElenaW [278]3 years ago
8 0
Solution is x+1
Hope this helps

yuradex [85]3 years ago
6 0

Answer:

if your trying to just muliply then the answer is 3x+3.

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WILL.MARK BRAINLEST. ( The length of a rectangular garden is 5m longer than its breadth .If its perimeter is 150 m,find the area
inessss [21]

Answer:

1400m^2

Step-by-step explanation:

Solution,

Let the breadth of the rectangle be x m, then the length of the rectangle will be x+5 m,

Now,

Perimeter of the rectangle=2(l+b)

150=2(x+5+x)

150=2(2x+5)

150=4x+10

150-10=4x

140=4x

140/4=x

35=x

So, the breadth of the rectangle=35 m

and length=(35+5)m=40m

Again,

Area of the rectangle=l×b

=40m×35m

=1400 m^2

I hope it helped U

stay safe stay happy

3 0
3 years ago
Read 2 more answers
A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.
mezya [45]
1. Divide wire b in parts x and b-x. 

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= \frac{1}{2}sin60^{o}side*side=   \frac{1}{2} \frac{ \sqrt{3} }{2}  (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}
A=\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2}  )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

 2 \pi r=x

so r= \frac{x}{2 \pi }

Area of circle = \pi  r^{2}= \pi  ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2}  }* x^{2} = \frac{1}{4 \pi } x^{2}

4. Let f(x)=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)=\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b

x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

6. So one part is \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) } and the other part is b-\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

4 0
3 years ago
Read 2 more answers
If I have 60 coins consisting of dimes and quarters and I have x dimes give an expression that would represent the number of qua
Nikolay [14]

Hey there!

Here is an exspression that would help recognize the amount of quarters you have:

X = Dimes

K = Quarters

X + K = 60 coins

Hope this helps!

3 0
3 years ago
Recycling Center A processes aluminum at a rate of 100 pounds per hour, while Recycling Center B processes aluminum at a rate of
maria [59]
I believe it is Recycling center A
6 0
3 years ago
Read 2 more answers
Students were surveyed about their favorite colors 1/4 preferred red, 1/8 preferred blue, 3/5 preferred green. If 15 students pr
const2013 [10]

Answer:

Let us assume the total number of students surveyed = x

Then

Number of students preferring red = x/4

Number of students preferring blue = x/8

Then

Number of students remaining = x - [(x/4) + (x/8)]

                                                  =x - [(2x + x)/8)

                                                  = x - (3x/8)

                                                  = (8x - 3x)/8

                                                  = 5x/8

Number of students preferring the color green = (3/5) * (5x/8)

                                                                          = 3x/8

We also know that the total number of students preferring the color green is 15

So

3x/8 = 15

3x = 15 * 8

x = (15 * 8)/3

  = 5 * 8

  = 40

So in total 40 students were surveyed. I hope the procedure is clear to you.

Step-by-step explanation:

6 0
3 years ago
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