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Monica [59]
3 years ago
13

What is the slope indicated in the table below.

Mathematics
2 answers:
alexgriva [62]3 years ago
4 0

Answer: y=-8/10x+29

Step-by-step explanation:

1. choose 2 points on form the chart

  • (10,21)(20,13)

2. y2-y1/x2-x1

  • 13-21/30-10=-8/10

3. y-y1=m(x-x1)

  • y-21=-8/10(x-10)

4. multiply

  • y-21=-8/10(x-10)
  • y-21=-8/10x+8

5. you need to isolate the variable so..

  • y-21=-8/10x+8
  • +21             +21
<h3>        y=-8/10x+29</h3>
miskamm [114]3 years ago
3 0
The answer to the problem is 5/-3
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How to solve this kind of question? <br><br><br> Show steps!
kirill [66]

Answer:

$130.34

Step-by-step explanation:

In this example, the total amount Myra has to pay is (original cost) + (total interest). This is because she has to pay interest because she bought clothes. Her total cost for the clothes is then 124.96+5.38=130.34

6 0
3 years ago
Simplify by combining like terms on each side of the equation. State your new equation.
vladimir1956 [14]

6x + x + x - 5 - 2 = 8 + 2x + x

combine like terms

8x -7 = 8 +3x

subtract 3x from each side

5x -7 = 8

add 7 to each side

5x = 15

divide by 5

x=3

Answer: 8x -7 = 8 +3x

x=3

6 0
3 years ago
The sum of the measures of two exterior angles of a triangle is 255°. What is the measure of the third exterior angle?
Juliette [100K]
Answer its b hope is helps 

5 0
3 years ago
The yearbook club had a meeting. The meeting had 20 people, which is four-fifths of the club. How many people are in the club?
Rama09 [41]
There are 32 people in the yearbook club

4 0
3 years ago
Read 2 more answers
Change each of the following points from rectangular coordinates to spherical coordinates and to cylindrical coordinates.
FromTheMoon [43]

Answer and Step-by-step explanation: Spherical coordinate describes a location of a point in space: one distance (ρ) and two angles (Ф,θ).To transform cartesian coordinates into spherical coordinates:

\rho = \sqrt{x^{2}+y^{2}+z^{2}}

\phi = cos^{-1}\frac{z}{\rho}

For angle θ:

  • If x > 0 and y > 0: \theta = tan^{-1}\frac{y}{x};
  • If x < 0: \theta = \pi + tan^{-1}\frac{y}{x};
  • If x > 0 and y < 0: \theta = 2\pi + tan^{-1}\frac{y}{x};

Calculating:

a) (4,2,-4)

\rho = \sqrt{4^{2}+2^{2}+(-4)^{2}} = 6

\phi = cos^{-1}(\frac{-4}{6})

\phi = cos^{-1}(\frac{-2}{3})

For θ, choose 1st option:

\theta = tan^{-1}(\frac{2}{4})

\theta = tan^{-1}(\frac{1}{2})

b) (0,8,15)

\rho = \sqrt{0^{2}+8^{2}+(15)^{2}} = 17

\phi = cos^{-1}(\frac{15}{17})

\theta = tan^{-1}\frac{y}{x}

The angle θ gives a tangent that doesn't exist. Analysing table of sine, cosine and tangent: θ = \frac{\pi}{2}

c) (√2,1,1)

\rho = \sqrt{(\sqrt{2} )^{2}+1^{2}+1^{2}} = 2

\phi = cos^{-1}(\frac{1}{2})

\phi = \frac{\pi}{3}

\theta = tan^{-1}\frac{1}{\sqrt{2} }

d) (−2√3,−2,3)

\rho = \sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}+3^{2}} = 5

\phi = cos^{-1}(\frac{3}{5})

Since x < 0, use 2nd option:

\theta = \pi + tan^{-1}\frac{1}{\sqrt{3} }

\theta = \pi + \frac{\pi}{6}

\theta = \frac{7\pi}{6}

Cilindrical coordinate describes a 3 dimension space: 2 distances (r and z) and 1 angle (θ). To express cartesian coordinates into cilindrical:

r=\sqrt{x^{2}+y^{2}}

Angle θ is the same as spherical coordinate;

z = z

Calculating:

a) (4,2,-4)

r=\sqrt{4^{2}+2^{2}} = \sqrt{20}

\theta = tan^{-1}\frac{1}{2}

z = -4

b) (0, 8, 15)

r=\sqrt{0^{2}+8^{2}} = 8

\theta = \frac{\pi}{2}

z = 15

c) (√2,1,1)

r=\sqrt{(\sqrt{2} )^{2}+1^{2}} = \sqrt{3}

\theta = \frac{\pi}{3}

z = 1

d) (−2√3,−2,3)

r=\sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}} = 4

\theta = \frac{7\pi}{6}

z = 3

5 0
3 years ago
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