Answer:
Step-by-step explanation:
In y = mx + b form, the slope can be found in the m position and the y intercept can be found in the b position.
4x - 2y = -6
-2y = -4x- 6
y = (-4/-2)x -(6/-2)
y = 2x + 3....slope here is 2, and y int is 3
3x + y = 3
y = -3x + 3.....slope here is -3, and y int is 3
B. slopes are different, y intercepts are the same
Answer:
He spent $15.51
Step-by-step explanation:
0.55x28.2=15.51
Hope this helps
^_^
I would say your friends assumption is wrong. Why?
Because, if you payed $2.40 for 3/4 pounds of grapes, your friend should pay more for an entire pound, not less.
Hope this helped! c:
yes, there are infinitety many polynomial that have exactly one real root just like your example, to determine the real root first let the real root is a, and the complex roots are b±ic the polynomial satisfy
-9x³ + 19x² + 17 = -(x - a)(x - b - ic)(x - b + ic)
9x³ - 19x² - 17 = (x - a)(x - b - ic)(x - b + ic)
Use the Pythagorean theorem since you are working with a right triangle:
a^2+b^2=c^2a2+b2=c2
The legs are a and b and the hypotenuse is c. The hypotenuse is always opposite the 90° angle. Insert the appropriate values:
0.8^2+0.6^2=c^20.82+0.62=c2
Solve for c. Simplify the exponents (x^2=x*xx2=x∗x ):
0.64+0.36=c^20.64+0.36=c2
Add:
1=c^21=c2
Isolate c. Find the square root of both sides:
\begin{gathered}\sqrt{1}=\sqrt{c^2}\\\\\sqrt{1}=c\end{gathered}1=c21=c
Simplify \sqrt{1}1 . Any root of 1 is 1:
c=c= ±11 *
c=1,-1c=1,−1
