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3 years ago

8

10) Data Distribution

1 answer:

murzikaleks [220]3 years ago

4 0

Answer:

mean 1.5

mode a 0

median 1

Step-by-step explanation:

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What is 7 (1+10p) + 8 (1 + 6p)

Komok [63]

Answer:

58p+15

Step-by-step explanation:

First, we want to get rid of the parentheses in the equation. To do that, let's start with 7(1+10p). We multiply 7 by each item in the parenthesis, and get 7+70p. Keep that little thing in mind, we will use it later. Next, same process with the other part, and we get 8+48p. We multiplied both parts out, so now we just add like terms. 7 and 8 don't have letters, so we add them to get 15. 10p and 48p do have letters, so we add those together and get 58p. We can't add that to the other numbers, because 58p is 58 times p, and 15 doesn't have that p so it wouldn't work without knowing p. What we are left with, by simplifying the problem, is 58p+15, or 15+58p. The order doesn't matter, as long as you have that answer.

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3 years ago

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On a coordinate plane, 2 exponential fuctions are shown. Function f (x) decreases from quadrant 2 into quadrant 1 and approaches

Gala2k [10]

Answer:

$g(x)=6(3)^x$

Step-by-step explanation:

We are given that

$f(x)=6(\frac{1}{3})^x$

Function f decreases from quadrant 2 to quadrant 1 and approaches y=0

It cut the y- axis at (0,6) and passing through the point (1,2).

Function g(x) approaches y=0 in quadrant 2 and increases into quadrant 1.

It passing through the point (-1,2) and cut the y-axis at point (0,6).

Reflection across y- axis:

Rule of transformation is given by

$(x,y)\rightarrow (-x,y)$

Using the rule then we get

$g(x)=6(\frac{1}{3})^{-x}=6(3)^x$

By using

$x^{-a}=\frac{1}{x^a}$

Substitute x=-1

$g(-1)=6\times (\frac{1}{3})=2$

Substitute x=0

$g(0)=6$

Therefore, $g(x)=6(3)^x$ is true.

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3 years ago

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I WILL AWARD BRAINLIEST HELP PLEASE what are the x and y intercepts for y=−9x−14

Veronika [31]

Answer:

x-intercept(s):

(−14/9,0)

y-intercept(s):

(0,−14)

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3 years ago

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A 2X2 square is centered at the origin. It is dilated by a factor of 3. What are coordinates of the vertices of the square?

Vesna [10]

Answer:

The vertices are:

A' = (-3, -3)

B' = (3, -3)

C' = (3, 3)

D' = (-3, 3)

Step-by-step explanation:

Given:

A 2 x 2 square is centered at the origin.

So, the center of the square is (0, 0)

Since it is 2 x 2 square, the side of the square is 2 units.

So, the vertices of the 2 x 2 square are A (-1, -1), B(1, -1), C(1. 1), D(-1, 1)

The above square is dilated by a factor of 3.

Let's name the dilated square A'B'C'D'

To find the coordinates of the vertices of dilated square, we need to multiply each vertices of ABCD by 3.

A(-1, -1) = 3(-1, -1) = A'(-3, -3)

B(1, -1) = 3(1, -1) = B'(3, -3)

C(1, 1) = 3(1, 1) = C'(3, 3)

D(-1, 1) = 3(-1, 1) = D'(-3, 3)

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3 years ago

A fair coin is flipped eight times. What is the probability of the coin landing heads up exactly 2 times?

dimulka [17.4K]

Answer:

50%

Step-by-step explanation:

no matter how many times it is flip you will get heads or tails.

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3 years ago

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