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3 years ago

Find the value of x. A.3 B.4 C.6 D.8

Mathematics

2 answers:

irinina [24]3 years ago

7 0

BE is half of CD. So,3*8=24

USPshnik [31]3 years ago

6 0

Answer:

D. 8

Step-by-step explanation:

BE is half of CD

48/2 = 24

3x = 24

Divide both by 3

3x/3 = 24/3

x = 8

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Luda [366]

Answer:

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3 years ago

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Sqrt(2x-6)=3-x Solve for x

soldi70 [24.7K]

Answer:

x = 3

Step-by-step explanation:

$\sqrt{2x - 6} = 3 - x$

Square both sides of the equation

$2x - 6 = (3 - x)^{2} = 9 - 6x + x^{2} \\$

$x^{2} - 8x + 15 = 0\\$

(x - 3)(x - 5) = 0

x = 3 or 5

Now, you must always check your results because a result may not satisfy the original equation.

If x = 3, then $\sqrt{2x - 6} = \sqrt{2(3) - 6} = \sqrt{6 - 6} = \sqrt{0} = 0$ and 3 - x = 3 - 3 = 0

So 3 satisfies the original.

If x = 5, then $\sqrt{2(5) - 6} = \sqrt{10 - 6} = \sqrt{4} = 2$ , but 3 - x = 3 - 5 = -2. Therefore, 5 does NOT satisfy the original equation.

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5 0

3 years ago

Identify the surface with the given vector equation. r(s, t) = s sin 4t, s2, s cos 4t

k0ka [10]

Answer:

Circular paraboloid

Step-by-step explanation:

Given ,

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Here, these are the respective $x,y,z$ axes components.

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Component along y axis $r_j : s^2$

Component along z axis $r_k : scos4t$

We see that , from the parameterised equation , $r_i^2+r_k^2=s^2sin^24t+s^2cos^24t\\r_i^2+r_k^2=s^2\\r_i^2+r_k^2=r_j$

This can also be written as :

$x^2+z^2=y$

This is similar to an equation of a parabola in 1 Dimension.

By fixing the value of z=0,

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By fixing the value of x=0,

We get $y=z^2$ which is equation of a parabola curving towards positive infinity of y-axis and in the y-z plane.

Thus by fixing the values of x and z alternatively , we get a CIRCULAR PARABOLOID.

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Answer:

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Step-by-step explanation:

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